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Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312?
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Point charges each equal to +q are placed at vertices of an equilatera...
Explanation:
Given:
- Three point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'.
- Net charge 'q' is placed at the circumcentre of the triangle.
Explanation:
Electric Field Due to a Point Charge:
- The electric field due to a point charge q at a distance r is given by E = k * q / r^2, where k = 1/(4πε₀).
Electric Field at the Circumcentre:
- The net electric field at the circumcentre due to the three charges is the vector sum of the electric fields due to each individual charge.
- Since the charges are equidistant from the circumcentre, the magnitudes of the electric fields due to each charge are the same.
- The net electric field at the circumcentre is zero because the electric fields due to the charges cancel out each other.
Net Charge at the Circumcentre:
- The net charge at the circumcentre is equal to the sum of the three charges placed at the vertices of the equilateral triangle.
- Therefore, the net charge q' at the circumcentre is 3q.
Final Answer:
- Therefore, the net charge 'q' placed at the circumcentre of the triangle is (C) zero.
Given:
- Three point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'.
- Net charge 'q' is placed at the circumcentre of the triangle.
Explanation:
Electric Field Due to a Point Charge:
- The electric field due to a point charge q at a distance r is given by E = k * q / r^2, where k = 1/(4πε₀).
Electric Field at the Circumcentre:
- The net electric field at the circumcentre due to the three charges is the vector sum of the electric fields due to each individual charge.
- Since the charges are equidistant from the circumcentre, the magnitudes of the electric fields due to each charge are the same.
- The net electric field at the circumcentre is zero because the electric fields due to the charges cancel out each other.
Net Charge at the Circumcentre:
- The net charge at the circumcentre is equal to the sum of the three charges placed at the vertices of the equilateral triangle.
- Therefore, the net charge q' at the circumcentre is 3q.
Final Answer:
- Therefore, the net charge 'q' placed at the circumcentre of the triangle is (C) zero.
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Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312?
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Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312?.
Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312?.
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Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312?, a detailed solution for Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? has been provided alongside types of Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? theory, EduRev gives you an
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