UPSC Exam > UPSC Questions > Point charges each equal to +q are placed at ...
Start Learning for Free
Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312?
Most Upvoted Answer
Point charges each equal to +q are placed at vertices of an equilatera...
Explanation:
Given:
- Three point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'.
- Net charge 'q' is placed at the circumcentre of the triangle.
Explanation:
Electric Field Due to a Point Charge:
- The electric field due to a point charge q at a distance r is given by E = k * q / r^2, where k = 1/(4πε₀).
Electric Field at the Circumcentre:
- The net electric field at the circumcentre due to the three charges is the vector sum of the electric fields due to each individual charge.
- Since the charges are equidistant from the circumcentre, the magnitudes of the electric fields due to each charge are the same.
- The net electric field at the circumcentre is zero because the electric fields due to the charges cancel out each other.
Net Charge at the Circumcentre:
- The net charge at the circumcentre is equal to the sum of the three charges placed at the vertices of the equilateral triangle.
- Therefore, the net charge q' at the circumcentre is 3q.
Final Answer:
- Therefore, the net charge 'q' placed at the circumcentre of the triangle is (C) zero.
Given:
- Three point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'.
- Net charge 'q' is placed at the circumcentre of the triangle.
Explanation:
Electric Field Due to a Point Charge:
- The electric field due to a point charge q at a distance r is given by E = k * q / r^2, where k = 1/(4πε₀).
Electric Field at the Circumcentre:
- The net electric field at the circumcentre due to the three charges is the vector sum of the electric fields due to each individual charge.
- Since the charges are equidistant from the circumcentre, the magnitudes of the electric fields due to each charge are the same.
- The net electric field at the circumcentre is zero because the electric fields due to the charges cancel out each other.
Net Charge at the Circumcentre:
- The net charge at the circumcentre is equal to the sum of the three charges placed at the vertices of the equilateral triangle.
- Therefore, the net charge q' at the circumcentre is 3q.
Final Answer:
- Therefore, the net charge 'q' placed at the circumcentre of the triangle is (C) zero.
Attention UPSC Students!
To make sure you are not studying endlessly, EduRev has designed UPSC study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UPSC.
|
Explore Courses for UPSC exam
|
|
Similar UPSC Doubts
Top Courses for UPSCView all
Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312?
Question Description
Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312?.
Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312?.
Solutions for Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? in English & in Hindi are available as part of our courses for UPSC.
Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? defined & explained in the simplest way possible. Besides giving the explanation of
Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312?, a detailed solution for Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? has been provided alongside types of Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? theory, EduRev gives you an
ample number of questions to practice Point charges each equal to +q are placed at vertices of an equilateral triangle of side 'l'. The net charge 'q' placed at circumcentre of triangle is (A) * 1/(4pi*epsilon_{0}) * \{(3q * q')/(l ^ 2)\}; B) 1/(4pi*epsilon_{0}) * \{(q * q')/(3l ^ 2)\} (C) zero D) ( 1 [299] 4πε, 1312? tests, examples and also practice UPSC tests.
|
|
Explore Courses for UPSC exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup