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A stone dropped in a well hits the water surface after 2s. What is the depth of the well and with what speed will the stone hit the water surface ? Assume the uniform acceleration due to gravity go be 9.8ms?
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A stone dropped in a well hits the water surface after 2s. What is the...
Depth of the well:
- Using the formula of motion s = ut + 1/2 at^2, where s is the depth of the well, u is the initial velocity (0 m/s as the stone is dropped), a is the acceleration due to gravity (9.8 m/s^2), and t is the time taken for the stone to hit the water surface (2 seconds).
- Substituting the values, we get s = 0 + 1/2 * 9.8 * (2)^2 = 19.6 meters. Therefore, the depth of the well is 19.6 meters.

Speed of the stone:
- To find the speed at which the stone hits the water surface, we can use the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity, and t is the time taken.
- Substituting the values, we get v = 0 + 9.8 * 2 = 19.6 m/s. Therefore, the stone will hit the water surface with a speed of 19.6 m/s.
By following the above calculations, we can determine the depth of the well and the speed at which the stone will hit the water surface accurately.
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A stone dropped in a well hits the water surface after 2s. What is the depth of the well and with what speed will the stone hit the water surface ? Assume the uniform acceleration due to gravity go be 9.8ms?
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