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Two particles of equal mass m go around a circle of radius R under action of their mutual gravitational attraction. The speed of each particle with respect to their centre of mass is [AIEEE 2011]
- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Two particles of equal mass m go around a circle of radius R under act...
Both their masses move in a circular path at exactly opposite diametrically ends with their centripetal forces being the common force of gravitation between them.
I.e. mv2/r = G.m.m/ 4r2
We get v =
I.e. mv2/r = G.m.m/ 4r2
We get v =
Most Upvoted Answer
Two particles of equal mass m go around a circle of radius R under act...
Mutual gravitational force= centrifugal force
Gm^2/(2r)^2= mv^2/r
I. e
Gm^2/4r^2 = mv^2/r
v = (Gm/4r )^1/2
Gm^2/(2r)^2= mv^2/r
I. e
Gm^2/4r^2 = mv^2/r
v = (Gm/4r )^1/2
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Two particles of equal mass m go around a circle of radius R under act...
Both their masses move in a circular path at exactly opposite diametrically ends with their centripetal forces being the common force of gravitation between them.
I.e. mv2/r = G.m.m/ 4r2
We get v =
I.e. mv2/r = G.m.m/ 4r2
We get v =
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Two particles of equal mass m go around a circle of radius R under action of their mutual gravitational attraction. The speed of each particle with respect to their centre of mass is [AIEEE 2011]a)b)c)d)Correct answer is option 'B'. Can you explain this answer?
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