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Two particles of equal mass m go around a circle of radius R under action of their mutual gravitational attraction. The speed of each particle with respect to their centre of mass is                [AIEEE 2011]
  • a)
  • b)
     
  • c)
     
  • d)
     
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Two particles of equal mass m go around a circle of radius R under act...
Both their masses move in a circular path at exactly opposite diametrically ends with their centripetal forces being the common force of gravitation between them.
I.e. mv2/r = G.m.m/ 4r2
We get v = 
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Most Upvoted Answer
Two particles of equal mass m go around a circle of radius R under act...
Mutual gravitational force= centrifugal force

Gm^2/(2r)^2= mv^2/r

I. e

Gm^2/4r^2 = mv^2/r

v = (Gm/4r )^1/2
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Community Answer
Two particles of equal mass m go around a circle of radius R under act...
Both their masses move in a circular path at exactly opposite diametrically ends with their centripetal forces being the common force of gravitation between them.
I.e. mv2/r = G.m.m/ 4r2
We get v = 
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Two particles of equal mass m go around a circle of radius R under action of their mutual gravitational attraction. The speed of each particle with respect to their centre of mass is [AIEEE 2011]a)b)c)d)Correct answer is option 'B'. Can you explain this answer?
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