A segment of DNA has 120 adenine and 120 cytosine bases. The total num...
According to Chargaff rule,
Adenine (A) is paired to Thymine (T)
Cytosine (C ) is paired to Guanine (G)
Here adenine residues =120, cytosine residues = 120
[A]=[T]
[A= 120]=[T=120]
[C]=[G]
[C= 120]=[G=120]
there fore total number of nucleotides = [A] + [T]+ [C]+[G] =120 * 4 = 480
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A segment of DNA has 120 adenine and 120 cytosine bases. The total num...
The total number of nucleotides in a DNA segment can be determined by adding up the number of adenine (A), thymine (T), cytosine (C), and guanine (G) bases present in the segment. In DNA, adenine pairs with thymine, and cytosine pairs with guanine. Therefore, the number of adenine bases will be equal to the number of thymine bases, and the number of cytosine bases will be equal to the number of guanine bases.
Given that the segment of DNA has 120 adenine bases and 120 cytosine bases, we can determine the number of thymine and guanine bases using the base pairing rule. Since adenine pairs with thymine and cytosine pairs with guanine, the number of thymine bases will also be 120, and the number of guanine bases will also be 120.
To calculate the total number of nucleotides, we add up the bases present in the segment. Each nucleotide consists of one base, so the total number of nucleotides will be equal to the sum of the bases.
Here is a breakdown of the calculation:
- Number of adenine bases: 120
- Number of thymine bases: 120
- Number of cytosine bases: 120
- Number of guanine bases: 120
Total number of nucleotides = Number of adenine bases + Number of thymine bases + Number of cytosine bases + Number of guanine bases
= 120 + 120 + 120 + 120
= 480
Therefore, the correct answer is option 'D' - 480 nucleotides.
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