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Conversion of excess-3 code to BCD code can be achieved by using
- a)4 x 16 decoder
- b)4 bit Full adder
- c)4 x 16 De-MUX
- d)4 bit Half adder
Correct answer is option 'C'. Can you explain this answer?
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Conversion of excess-3 code to BCD code can be achieved by usinga)4 x ...
The number of AND gates required will be equal to the number of outputs in a demultiplexer.
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Conversion of excess-3 code to BCD code can be achieved by usinga)4 x ...
Conversion of Excess-3 Code to BCD Code using 4x16 De-MUX:
Excess-3 Code: It is a binary code which is obtained by adding 3 to the decimal equivalent of a given decimal digit. For example, the excess-3 code for decimal digit 2 is (0010 + 0011) = 0101.
BCD Code: It is a binary code in which each decimal digit is represented by a 4-bit binary code. For example, the BCD code for decimal digit 2 is 0010.
Conversion of Excess-3 Code to BCD Code:
The conversion of Excess-3 code to BCD code can be achieved by using a 4x16 De-MUX. The 4x16 De-MUX has 4 input lines and 16 output lines.
The 4 input lines of the De-MUX are connected to the Excess-3 code input lines. The 16 output lines of the De-MUX are connected to the BCD code output lines.
The truth table for the 4x16 De-MUX is as follows:
| A | B | C | D | Y0 | Y1 | Y2 | Y3 | Y4 | Y5 | Y6 | Y7 | Y8 | Y9 | Y10 | Y11 | Y12 | Y13 | Y14 | Y15 |
|---|---|---|---|----|----|----|----|----|----|----|----|----|----|-----|-----|-----|-----|-----|-----|
| 0 | 0 | 0 | 0 | D0 | D1 | D2 | D3 | D4 | D5 | D6 | D7 | D8 | D9 | D10 | D11 | D12 | D13 | D14 | D15 |
| 0 | 0 | 0 | 1 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 0 | 0 | 1 | 0 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 0 | 0 | 1 | 1 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 0 | 1 | 0 | 0 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 0 | 1 | 0 | 1 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 0 |
Excess-3 Code: It is a binary code which is obtained by adding 3 to the decimal equivalent of a given decimal digit. For example, the excess-3 code for decimal digit 2 is (0010 + 0011) = 0101.
BCD Code: It is a binary code in which each decimal digit is represented by a 4-bit binary code. For example, the BCD code for decimal digit 2 is 0010.
Conversion of Excess-3 Code to BCD Code:
The conversion of Excess-3 code to BCD code can be achieved by using a 4x16 De-MUX. The 4x16 De-MUX has 4 input lines and 16 output lines.
The 4 input lines of the De-MUX are connected to the Excess-3 code input lines. The 16 output lines of the De-MUX are connected to the BCD code output lines.
The truth table for the 4x16 De-MUX is as follows:
| A | B | C | D | Y0 | Y1 | Y2 | Y3 | Y4 | Y5 | Y6 | Y7 | Y8 | Y9 | Y10 | Y11 | Y12 | Y13 | Y14 | Y15 |
|---|---|---|---|----|----|----|----|----|----|----|----|----|----|-----|-----|-----|-----|-----|-----|
| 0 | 0 | 0 | 0 | D0 | D1 | D2 | D3 | D4 | D5 | D6 | D7 | D8 | D9 | D10 | D11 | D12 | D13 | D14 | D15 |
| 0 | 0 | 0 | 1 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 0 | 0 | 1 | 0 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 0 | 0 | 1 | 1 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 0 | 1 | 0 | 0 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 0 | 1 | 0 | 1 | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 0 |
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Community Answer
Conversion of excess-3 code to BCD code can be achieved by usinga)4 x ...
Demux means only one input and many output s.according to above question we know that excess-3 means adding of three to each number.for example 0+3=0011 1+3=0100 2+3=0101 . . . 12+3=1111
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Conversion of excess-3 code to BCD code can be achieved by usinga)4 x 16 decoderb)4 bit Full adderc)4 x 16 De-MUXd)4 bit Half adderCorrect answer is option 'C'. Can you explain this answer?
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