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Find out mole fraction of NaOH present in a solution which is prepared by dissolving 240g of NaOH in 840g of CH3OH?
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Find out mole fraction of NaOH present in a solution which is prepared...
Calculating Mole Fraction of NaOH in the Solution
- Step 1: Calculate the moles of NaOH
Given:
Mass of NaOH = 240g
Molar mass of NaOH = 40 g/mol
Number of moles of NaOH = Mass/Molar mass
Number of moles of NaOH = 240g / 40 g/mol
Number of moles of NaOH = 6 moles
- Step 2: Calculate the moles of CH3OH
Given:
Mass of CH3OH = 840g
Molar mass of CH3OH = 32 g/mol
Number of moles of CH3OH = Mass/Molar mass
Number of moles of CH3OH = 840g / 32 g/mol
Number of moles of CH3OH = 26.25 moles
- Step 3: Calculate the total moles of the solution
Total moles of the solution = Moles of NaOH + Moles of CH3OH
Total moles of the solution = 6 moles + 26.25 moles
Total moles of the solution = 32.25 moles
- Step 4: Calculate the mole fraction of NaOH
Mole fraction of NaOH = Moles of NaOH / Total moles of the solution
Mole fraction of NaOH = 6 moles / 32.25 moles
Mole fraction of NaOH ≈ 0.186
Therefore, the mole fraction of NaOH in the solution prepared by dissolving 240g of NaOH in 840g of CH3OH is approximately 0.186.
- Step 1: Calculate the moles of NaOH
Given:
Mass of NaOH = 240g
Molar mass of NaOH = 40 g/mol
Number of moles of NaOH = Mass/Molar mass
Number of moles of NaOH = 240g / 40 g/mol
Number of moles of NaOH = 6 moles
- Step 2: Calculate the moles of CH3OH
Given:
Mass of CH3OH = 840g
Molar mass of CH3OH = 32 g/mol
Number of moles of CH3OH = Mass/Molar mass
Number of moles of CH3OH = 840g / 32 g/mol
Number of moles of CH3OH = 26.25 moles
- Step 3: Calculate the total moles of the solution
Total moles of the solution = Moles of NaOH + Moles of CH3OH
Total moles of the solution = 6 moles + 26.25 moles
Total moles of the solution = 32.25 moles
- Step 4: Calculate the mole fraction of NaOH
Mole fraction of NaOH = Moles of NaOH / Total moles of the solution
Mole fraction of NaOH = 6 moles / 32.25 moles
Mole fraction of NaOH ≈ 0.186
Therefore, the mole fraction of NaOH in the solution prepared by dissolving 240g of NaOH in 840g of CH3OH is approximately 0.186.
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Find out mole fraction of NaOH present in a solution which is prepared by dissolving 240g of NaOH in 840g of CH3OH?
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Find out mole fraction of NaOH present in a solution which is prepared by dissolving 240g of NaOH in 840g of CH3OH? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Find out mole fraction of NaOH present in a solution which is prepared by dissolving 240g of NaOH in 840g of CH3OH? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find out mole fraction of NaOH present in a solution which is prepared by dissolving 240g of NaOH in 840g of CH3OH?.
Find out mole fraction of NaOH present in a solution which is prepared by dissolving 240g of NaOH in 840g of CH3OH? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Find out mole fraction of NaOH present in a solution which is prepared by dissolving 240g of NaOH in 840g of CH3OH? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find out mole fraction of NaOH present in a solution which is prepared by dissolving 240g of NaOH in 840g of CH3OH?.
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