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If alpha and beeta are the zeroes of x2+x-2, then find apha×beeta2 + alpha2 ×beeta?
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If alpha and beeta are the zeroes of x2+x-2, then find apha×beeta2 + a...
Given information:
- Zeroes of the quadratic equation x² + x - 2 are alpha and beta.

Formula:
- If alpha and beta are the zeroes of a quadratic equation ax² + bx + c = 0, then the sum of the zeroes is -b/a and the product of the zeroes is c/a.

Finding the values of alpha and beta:
- In the given equation x² + x - 2 = 0, a = 1, b = 1, and c = -2.
- Sum of the zeroes (alpha + beta) = -b/a = -1/1 = -1.
- Product of the zeroes (alpha * beta) = c/a = -2/1 = -2.
- Therefore, alpha = 1 and beta = -2.

Calculating the required expression:
- We need to find alpha * beta² + alpha² * beta.
- Substituting the values of alpha and beta, we get:
- alpha * beta² + alpha² * beta
= 1 * (-2)² + 1² * (-2)
= 1 * 4 + 1 * (-2)
= 4 - 2
= 2.
Therefore, the value of alpha * beta² + alpha² * beta is 2.
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If alpha and beeta are the zeroes of x2+x-2, then find apha×beeta2 + alpha2 ×beeta?
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