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A particle is projected at t equals to zero with a velocity 120 m/s angle 60 degree to the horizontal take acceleration due to gravity is 10 M per second square calculate modulus of the things in velocity of the particle in metre per second and the time interval from T equals to 2.8 seconds to 3.1 second?
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A particle is projected at t equals to zero with a velocity 120 m/s an...
Given Data:
- Initial velocity (u) = 120 m/s
- Angle of projection (θ) = 60 degrees
- Acceleration due to gravity (g) = 10 m/s^2
Calculating the Modulus of the Final Velocity:
- The horizontal component of the initial velocity (u) = u * cos(θ) = 120 * cos(60) = 60 m/s
- The vertical component of the initial velocity (u) = u * sin(θ) = 120 * sin(60) = 103.92 m/s
- The time taken to reach maximum height (t) = (u sin(θ)) / g = (103.92) / (10) = 10.39 seconds
- The maximum height reached (H) = (u^2 sin^2(θ)) / (2g) = (120^2 * sin^2(60)) / (2 * 10) = 103.92 m
- The time of flight (T) = 2 * t = 2 * 10.39 = 20.78 seconds
- The range (R) = (u^2 sin(2θ)) / g = (120^2 * sin(120)) / 10 = 207.84 m
- The final velocity (v) = u = 120 m/s
Calculating the Time Interval:
- At t = 2.8 seconds, the vertical component of velocity (v) = u sin(θ) - gt = 103.92 - (10 * 2.8) = 75.52 m/s
- At t = 3.1 seconds, the vertical component of velocity (v) = u sin(θ) - gt = 103.92 - (10 * 3.1) = 72.82 m/s
Conclusion:
- The modulus of the final velocity of the particle is 120 m/s.
- The time interval from t = 2.8 seconds to t = 3.1 seconds is 0.3 seconds.
- Initial velocity (u) = 120 m/s
- Angle of projection (θ) = 60 degrees
- Acceleration due to gravity (g) = 10 m/s^2
Calculating the Modulus of the Final Velocity:
- The horizontal component of the initial velocity (u) = u * cos(θ) = 120 * cos(60) = 60 m/s
- The vertical component of the initial velocity (u) = u * sin(θ) = 120 * sin(60) = 103.92 m/s
- The time taken to reach maximum height (t) = (u sin(θ)) / g = (103.92) / (10) = 10.39 seconds
- The maximum height reached (H) = (u^2 sin^2(θ)) / (2g) = (120^2 * sin^2(60)) / (2 * 10) = 103.92 m
- The time of flight (T) = 2 * t = 2 * 10.39 = 20.78 seconds
- The range (R) = (u^2 sin(2θ)) / g = (120^2 * sin(120)) / 10 = 207.84 m
- The final velocity (v) = u = 120 m/s
Calculating the Time Interval:
- At t = 2.8 seconds, the vertical component of velocity (v) = u sin(θ) - gt = 103.92 - (10 * 2.8) = 75.52 m/s
- At t = 3.1 seconds, the vertical component of velocity (v) = u sin(θ) - gt = 103.92 - (10 * 3.1) = 72.82 m/s
Conclusion:
- The modulus of the final velocity of the particle is 120 m/s.
- The time interval from t = 2.8 seconds to t = 3.1 seconds is 0.3 seconds.
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A particle is projected at t equals to zero with a velocity 120 m/s angle 60 degree to the horizontal take acceleration due to gravity is 10 M per second square calculate modulus of the things in velocity of the particle in metre per second and the time interval from T equals to 2.8 seconds to 3.1 second?
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A particle is projected at t equals to zero with a velocity 120 m/s angle 60 degree to the horizontal take acceleration due to gravity is 10 M per second square calculate modulus of the things in velocity of the particle in metre per second and the time interval from T equals to 2.8 seconds to 3.1 second? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A particle is projected at t equals to zero with a velocity 120 m/s angle 60 degree to the horizontal take acceleration due to gravity is 10 M per second square calculate modulus of the things in velocity of the particle in metre per second and the time interval from T equals to 2.8 seconds to 3.1 second? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is projected at t equals to zero with a velocity 120 m/s angle 60 degree to the horizontal take acceleration due to gravity is 10 M per second square calculate modulus of the things in velocity of the particle in metre per second and the time interval from T equals to 2.8 seconds to 3.1 second?.
A particle is projected at t equals to zero with a velocity 120 m/s angle 60 degree to the horizontal take acceleration due to gravity is 10 M per second square calculate modulus of the things in velocity of the particle in metre per second and the time interval from T equals to 2.8 seconds to 3.1 second? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A particle is projected at t equals to zero with a velocity 120 m/s angle 60 degree to the horizontal take acceleration due to gravity is 10 M per second square calculate modulus of the things in velocity of the particle in metre per second and the time interval from T equals to 2.8 seconds to 3.1 second? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is projected at t equals to zero with a velocity 120 m/s angle 60 degree to the horizontal take acceleration due to gravity is 10 M per second square calculate modulus of the things in velocity of the particle in metre per second and the time interval from T equals to 2.8 seconds to 3.1 second?.
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