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I stone is thrown in a vertical upward direction with a velocity 10 m per second the acceleration of the stone during its motion 10 m per second square in the upward direction what will be the height attend by the stone and how much time will take to reach there?
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I stone is thrown in a vertical upward direction with a velocity 10 m ...
Height attained by the stone:
The height attained by the stone can be calculated using the kinematic equation:
\[ v_f^2 = v_i^2 + 2a \cdot d \]
where:
\( v_f = 0 \) (final velocity is 0 at the highest point)
\( v_i = 10 \, \text{m/s} \) (initial velocity)
\( a = -10 \, \text{m/s}^2 \) (acceleration due to gravity, negative because it's in the opposite direction to the motion)
\( d \) is the height we want to find.
Solving for \( d \):
\[ 0 = (10)^2 + 2 \cdot (-10) \cdot d \]
\[ 0 = 100 - 20d \]
\[ 20d = 100 \]
\[ d = 5 \, \text{m} \]
Therefore, the stone attains a height of 5 meters.
Time taken to reach the height:
The time taken to reach the maximum height can be found using the kinematic equation:
\[ v_f = v_i + a \cdot t \]
where:
\( v_f = 0 \) (final velocity is 0 at the highest point)
\( v_i = 10 \, \text{m/s} \) (initial velocity)
\( a = -10 \, \text{m/s}^2 \) (acceleration due to gravity, negative because it's in the opposite direction to the motion)
\( t \) is the time we want to find.
Solving for \( t \):
\[ 0 = 10 + (-10) \cdot t \]
\[ -10t = -10 \]
\[ t = 1 \, \text{s} \]
Therefore, the stone takes 1 second to reach the height of 5 meters.
The height attained by the stone can be calculated using the kinematic equation:
\[ v_f^2 = v_i^2 + 2a \cdot d \]
where:
\( v_f = 0 \) (final velocity is 0 at the highest point)
\( v_i = 10 \, \text{m/s} \) (initial velocity)
\( a = -10 \, \text{m/s}^2 \) (acceleration due to gravity, negative because it's in the opposite direction to the motion)
\( d \) is the height we want to find.
Solving for \( d \):
\[ 0 = (10)^2 + 2 \cdot (-10) \cdot d \]
\[ 0 = 100 - 20d \]
\[ 20d = 100 \]
\[ d = 5 \, \text{m} \]
Therefore, the stone attains a height of 5 meters.
Time taken to reach the height:
The time taken to reach the maximum height can be found using the kinematic equation:
\[ v_f = v_i + a \cdot t \]
where:
\( v_f = 0 \) (final velocity is 0 at the highest point)
\( v_i = 10 \, \text{m/s} \) (initial velocity)
\( a = -10 \, \text{m/s}^2 \) (acceleration due to gravity, negative because it's in the opposite direction to the motion)
\( t \) is the time we want to find.
Solving for \( t \):
\[ 0 = 10 + (-10) \cdot t \]
\[ -10t = -10 \]
\[ t = 1 \, \text{s} \]
Therefore, the stone takes 1 second to reach the height of 5 meters.
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I stone is thrown in a vertical upward direction with a velocity 10 m per second the acceleration of the stone during its motion 10 m per second square in the upward direction what will be the height attend by the stone and how much time will take to reach there?
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I stone is thrown in a vertical upward direction with a velocity 10 m per second the acceleration of the stone during its motion 10 m per second square in the upward direction what will be the height attend by the stone and how much time will take to reach there? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about I stone is thrown in a vertical upward direction with a velocity 10 m per second the acceleration of the stone during its motion 10 m per second square in the upward direction what will be the height attend by the stone and how much time will take to reach there? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for I stone is thrown in a vertical upward direction with a velocity 10 m per second the acceleration of the stone during its motion 10 m per second square in the upward direction what will be the height attend by the stone and how much time will take to reach there?.
I stone is thrown in a vertical upward direction with a velocity 10 m per second the acceleration of the stone during its motion 10 m per second square in the upward direction what will be the height attend by the stone and how much time will take to reach there? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about I stone is thrown in a vertical upward direction with a velocity 10 m per second the acceleration of the stone during its motion 10 m per second square in the upward direction what will be the height attend by the stone and how much time will take to reach there? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for I stone is thrown in a vertical upward direction with a velocity 10 m per second the acceleration of the stone during its motion 10 m per second square in the upward direction what will be the height attend by the stone and how much time will take to reach there?.
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