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27. 3.6 gm of a gas at 27°C occupied the same volume as 0.18 gm of hydrogen at 27°C and at the same pressure. The molecular weight of gas is
(a) 4gmo * l ^ - 1
(b) 20gmo * l ^ - 1
40gmo * l ^ - 1
(d) 36gmo * l ^ - 1?
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27. 3.6 gm of a gas at 27°C occupied the same volume as 0.18 gm of hyd...
Given Information:
- Mass of gas = 3.6 gm
- Mass of hydrogen = 0.18 gm
- Temperature = 27°C
- Pressure is the same for both gases

To find:
Molecular weight of the gas

Explanation:
- The ideal gas equation is given by PV = nRT
- Since the pressure and volume are the same for both gases, we can ignore them in this case
- Therefore, we have n1 = n2 (number of moles of gas 1 = number of moles of gas 2)

Calculations:
- Number of moles of gas = Mass / Molar mass
- For the gas: n1 = 3.6 / M1
- For hydrogen: n2 = 0.18 / 2 (molar mass of hydrogen = 2)
- Since n1 = n2, we have 3.6 / M1 = 0.18 / 2
- Solving for M1, we get: M1 = 3.6 * 2 / 0.18 = 40 g/mol

Conclusion:
- The molecular weight of the gas is 40 g/mol. Therefore, the correct option is (b) 20 gmo * l ^ -1.
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27. 3.6 gm of a gas at 27°C occupied the same volume as 0.18 gm of hydrogen at 27°C and at the same pressure. The molecular weight of gas is(a) 4gmo * l ^ - 1(b) 20gmo * l ^ - 140gmo * l ^ - 1(d) 36gmo * l ^ - 1?
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Solutions for 27. 3.6 gm of a gas at 27°C occupied the same volume as 0.18 gm of hydrogen at 27°C and at the same pressure. The molecular weight of gas is(a) 4gmo * l ^ - 1(b) 20gmo * l ^ - 140gmo * l ^ - 1(d) 36gmo * l ^ - 1? in English & in Hindi are available as part of our courses for UPSC. Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
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