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Roots of equation 2x²+3x+7=0 are a and b. The value of ab-¹+ba-¹?
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Roots of equation 2x²+3x+7=0 are a and b. The value of ab-¹+ba-¹?
Roots of the equation
The given equation is 2x²+3x+7=0. Let's assume the roots of the equation are a and b.

Finding the sum and product of the roots
By Vieta's formulas, the sum of the roots is given by: a + b = -3/2 and the product of the roots is given by: ab = 7/2.

Finding the value of ab⁻¹ + ba⁻¹
We know that ab⁻¹ + ba⁻¹ = a/b + b/a.
To find this value, let's first find the individual values of a/b and b/a.
a/b = 1/b + 1/a = (a + b)/ab = -3/2 / 7/2 = -3/7.
Similarly, b/a = 1/a + 1/b = (a + b)/ab = -3/7.
Therefore, ab⁻¹ + ba⁻¹ = -3/7 + (-3/7) = -6/7.
Therefore, the value of ab⁻¹ + ba⁻¹ is -6/7.
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Roots of equation 2x²+3x+7=0 are a and b. The value of ab-¹+ba-¹?
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