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If I= [ cos - sin - √8-sin2 인 de = a sin -1 sin +cos 0 b +C then 0 ordered pair (a, b) is [JEE Main P-I 2021] a. (1, 3) b. (3, 1) c. (1, 1) d. (-1, 3)?
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If I= [ cos - sin - √8-sin2 인 de = a sin -1 sin +cos 0 b +C then 0 ord...
Given Equation:
I = cosθ - sinθ - √8 - sin^2θ dθ = a sin^-1(sinθ) + cosθ + b dθ + C
Finding the values of a and b:
- Compare the given equation with the standard form of integration formulas to determine the values of a and b.
Comparing the given equation with standard forms:
- The given equation can be written as:
∫(cosθ - sinθ - √8 - sin^2θ) dθ = a ∫sin^-1(sinθ) dθ + ∫cosθ dθ + b ∫dθ + C
Identifying the values:
- Comparing the terms on both sides of the equation, we can determine the values of a and b.
- From the comparison, we get:
a = 1 and b = 3
Therefore, the ordered pair (a, b) is:
- The values of a and b are:
a = 1, b = 3
Answer:
- Therefore, the correct ordered pair is (1, 3) as option a.
I = cosθ - sinθ - √8 - sin^2θ dθ = a sin^-1(sinθ) + cosθ + b dθ + C
Finding the values of a and b:
- Compare the given equation with the standard form of integration formulas to determine the values of a and b.
Comparing the given equation with standard forms:
- The given equation can be written as:
∫(cosθ - sinθ - √8 - sin^2θ) dθ = a ∫sin^-1(sinθ) dθ + ∫cosθ dθ + b ∫dθ + C
Identifying the values:
- Comparing the terms on both sides of the equation, we can determine the values of a and b.
- From the comparison, we get:
a = 1 and b = 3
Therefore, the ordered pair (a, b) is:
- The values of a and b are:
a = 1, b = 3
Answer:
- Therefore, the correct ordered pair is (1, 3) as option a.
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If I= [ cos - sin - √8-sin2 인 de = a sin -1 sin +cos 0 b +C then 0 ordered pair (a, b) is [JEE Main P-I 2021] a. (1, 3) b. (3, 1) c. (1, 1) d. (-1, 3)?
Question Description
If I= [ cos - sin - √8-sin2 인 de = a sin -1 sin +cos 0 b +C then 0 ordered pair (a, b) is [JEE Main P-I 2021] a. (1, 3) b. (3, 1) c. (1, 1) d. (-1, 3)? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about If I= [ cos - sin - √8-sin2 인 de = a sin -1 sin +cos 0 b +C then 0 ordered pair (a, b) is [JEE Main P-I 2021] a. (1, 3) b. (3, 1) c. (1, 1) d. (-1, 3)? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If I= [ cos - sin - √8-sin2 인 de = a sin -1 sin +cos 0 b +C then 0 ordered pair (a, b) is [JEE Main P-I 2021] a. (1, 3) b. (3, 1) c. (1, 1) d. (-1, 3)?.
If I= [ cos - sin - √8-sin2 인 de = a sin -1 sin +cos 0 b +C then 0 ordered pair (a, b) is [JEE Main P-I 2021] a. (1, 3) b. (3, 1) c. (1, 1) d. (-1, 3)? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about If I= [ cos - sin - √8-sin2 인 de = a sin -1 sin +cos 0 b +C then 0 ordered pair (a, b) is [JEE Main P-I 2021] a. (1, 3) b. (3, 1) c. (1, 1) d. (-1, 3)? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If I= [ cos - sin - √8-sin2 인 de = a sin -1 sin +cos 0 b +C then 0 ordered pair (a, b) is [JEE Main P-I 2021] a. (1, 3) b. (3, 1) c. (1, 1) d. (-1, 3)?.
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