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A body covers first one third of the distance with a velocity a the second third of distance with a velocity b and the remaining with velocity c .the avarage velocity is?
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A body covers first one third of the distance with a velocity a the se...
Explanation:

Given data:
- Distance is divided into three equal parts.
- First part is covered with velocity a.
- Second part is covered with velocity b.
- Third part is covered with velocity c.

Calculating average velocity:
- Let the total distance be D.
- Distance covered with velocity a = D/3
- Distance covered with velocity b = D/3
- Distance covered with velocity c = D/3
- Time taken to cover first part = (D/3) / a = D/3a
- Time taken to cover second part = (D/3) / b = D/3b
- Time taken to cover third part = (D/3) / c = D/3c
- Total time taken = D/3a + D/3b + D/3c = D(1/a + 1/b + 1/c)/3
- Total distance = D
- Total time = D(1/a + 1/b + 1/c)/3
- Average velocity = Total distance / Total time = D / (D(1/a + 1/b + 1/c)/3) = 3 / (1/a + 1/b + 1/c)
Therefore, the average velocity is 3 / (1/a + 1/b + 1/c).
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A body covers first one third of the distance with a velocity a the second third of distance with a velocity b and the remaining with velocity c .the avarage velocity is?
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