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If alpha and beta are the zeroes of the quadratic polynomial p(x)=2xsquare+11x+5 then find 1/alpha+1/beta-2alphabeta?
Most Upvoted Answer
If alpha and beta are the zeroes of the quadratic polynomial p(x)=2xsq...
Given Information:
The quadratic polynomial is p(x) = 2x^2 + 11x + 5
The zeroes of the polynomial are alpha and beta

Formula:
If alpha and beta are the zeroes of a quadratic polynomial ax^2 + bx + c, then:
1/alpha + 1/beta = (alpha + beta) / (alpha * beta)
2alpha * beta = c / a

Solution:

Finding Sum and Product of Zeroes:
From the given polynomial, a = 2, b = 11, and c = 5
Sum of zeroes, alpha + beta = -b/a = -11/2
Product of zeroes, alpha * beta = c/a = 5/2

Calculating 1/alpha + 1/beta - 2alpha*beta:
1/alpha + 1/beta = (alpha + beta) / (alpha * beta)
= (-11/2) / (5/2)
= -11/5
2alpha*beta = c / a = 5/2
Therefore, 1/alpha + 1/beta - 2alpha*beta = -11/5 - 5/2
= (-11*2 - 5*5) / 5*2
= (-22 - 25) / 10
= -47/10
Hence, 1/alpha + 1/beta - 2alpha*beta = -47/10
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If alpha and beta are the zeroes of the quadratic polynomial p(x)=2xsquare+11x+5 then find 1/alpha+1/beta-2alphabeta?
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