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The first term of gp exceeds the second term by 2 and s ♾️=50 find the gp?
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The first term of gp exceeds the second term by 2 and s ♾️=50 find the...
Given Information:
- First term of GP exceeds the second term by 2.
- Sum of the first 50 terms of the GP is 50.

Let's Solve the Problem:

Step 1: Setting up the GP
Let the first term of the GP be x. Then the second term would be x + 2, as per the given information.

Step 2: Finding the Common Ratio
The sum of the first 50 terms of a GP can be calculated using the formula:
Sn = a*(1 - rn)/(1 - r), where a is the first term, r is the common ratio, and n is the number of terms.
Since Sn = 50 and n = 50, we can substitute the values and solve for r.

Step 3: Finding the GP
Once we have the common ratio, we can find the GP by substituting the values of the first term (x) and the common ratio (r) into the formula for a GP:
a, ar, ar2, ar3, ...
Thus, by following these steps, we can determine the GP given the conditions provided.
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The first term of gp exceeds the second term by 2 and s ♾️=50 find the gp?
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The first term of gp exceeds the second term by 2 and s ♾️=50 find the gp? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The first term of gp exceeds the second term by 2 and s ♾️=50 find the gp? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The first term of gp exceeds the second term by 2 and s ♾️=50 find the gp?.
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