Calculating the Probability of Getting a 5 At Least Once When a Dice is Thrown Twice

Introduction:
When a dice is thrown twice, we need to find the probability of getting a 5 at least once in the two throws.

Calculating the Total Number of Outcomes:
When a dice is thrown, there are 6 possible outcomes (1, 2, 3, 4, 5, 6). So, when thrown twice, the total number of outcomes = 6 x 6 = 36.

Calculating the Number of Favorable Outcomes:
To get a 5 at least once, we can have the following scenarios:
1. Getting a 5 in the first throw and any number in the second throw.
2. Getting any number in the first throw and a 5 in the second throw.
3. Getting a 5 in both throws.
So, the number of favorable outcomes = 1 (5 in first throw) x 5 (any number in second throw) + 5 (any number in first throw) x 1 (5 in second throw) + 1 (5 in both throws) = 11.

Calculating the Probability:
Probability = Number of Favorable Outcomes / Total Number of Outcomes
Probability = 11 / 36 ≈ 0.3056
Therefore, the probability of getting a 5 at least once when a dice is thrown twice is approximately 0.3056 or 30.56%.