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In a transformer the primary has 500 turns and secondary has 50 turn. 100 volts are applied to the primary coil, the voltage developed in the secondary will be
  • a)
    1 V
  • b)
    10 V
  • c)
    1000 V
  • d)
    10000 V
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In a transformer the primary has 500 turns and secondary has 50 turn. ...
Calculation of Voltage in the Secondary Coil:
To calculate the voltage developed in the secondary coil of the transformer, we can use the formula:
\[
\frac{V_p}{V_s} = \frac{N_p}{N_s}
\]
Where:
- \(V_p\) = Voltage in the primary coil (100 V)
- \(V_s\) = Voltage in the secondary coil (to be calculated)
- \(N_p\) = Number of turns in the primary coil (500 turns)
- \(N_s\) = Number of turns in the secondary coil (50 turns)

Calculating Voltage in the Secondary Coil:
Substitute the given values into the formula:
\[
\frac{100}{V_s} = \frac{500}{50}
\]
Simplify the equation:
\[
\frac{100}{V_s} = 10
\]
Now, solve for \(V_s\):
\[
V_s = \frac{100}{10} = 10 \text{ volts}
\]
Therefore, the voltage developed in the secondary coil of the transformer is 10 volts.

Conclusion:
The correct answer is option 'b) 10 V'. This calculation demonstrates the relationship between the number of turns in the primary and secondary coils of a transformer and how it affects the voltage developed in each coil.
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In a transformer the primary has 500 turns and secondary has 50 turn. 100 volts are applied to the primary coil, the voltage developed in the secondary will bea)1 Vb)10 Vc)1000 Vd)10000 VCorrect answer is option 'B'. Can you explain this answer?
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