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An ideal transformer has 500 and the 1000 turns in the primary and the secondary coil. If the DC voltage of 120 V is applied to the primary coil, then the emf produced at the secondary coil will be:
  • a)
    60 V
  • b)
    240 V
  • c)
    30 V
  • d)
    Zero
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
An ideal transformer has 500 and the 1000 turns in the primary and the...
Given: DC voltage EP = 120 V (Primary coil)
  • The transformer works on the principle of mutual inductance.
  • To induce emf in the secondary coil of the transformer, the magnetic flux associated with the secondary coil must change with respect to time.
  • When the DC voltage is applied at the primary coil of the transformer, the magnetic flux associated with the coil will remain constant with respect to time. So the emf will not induce at the secondary coil.
  • Therefore, when the DC voltage is applied at the primary coil, the induced emf in the secondary coil will be zero.
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Community Answer
An ideal transformer has 500 and the 1000 turns in the primary and the...
Given:
Primary turns (N1) = 500
Secondary turns (N2) = 1000
DC voltage applied to the primary coil (V1) = 120V

To find:
The emf produced at the secondary coil (V2)

Solution:
The ideal transformer is a device that transfers electrical energy from one circuit to another through electromagnetic induction. It works on the principle of Faraday's law of electromagnetic induction.

Faraday's law of electromagnetic induction:
The induced emf (voltage) in a coil is proportional to the rate of change of magnetic flux passing through the coil.

Step 1: Calculate the magnetic flux in the primary coil:
The magnetic flux (Φ) is given by the formula:
Φ = N1Φ1
where N1 is the number of turns in the primary coil and Φ1 is the magnetic flux.

Step 2: Calculate the emf induced in the primary coil:
The emf induced in the primary coil (V1) is given by the formula:
V1 = -N1(dΦ1 / dt)
where dΦ1 / dt is the rate of change of magnetic flux.

Since the DC voltage is applied to the primary coil, there is no change in magnetic flux (dΦ1 / dt = 0). Therefore, the emf induced in the primary coil is zero.

Step 3: Apply the transformer equation:
The transformer equation relates the voltages and turns in the primary and secondary coils.
V1 / N1 = V2 / N2

Substituting the values:
V1 / 500 = V2 / 1000

Step 4: Calculate the emf induced in the secondary coil:
Rearranging the equation:
V2 = (V1 * N2) / N1
V2 = (120V * 1000) / 500
V2 = 240V

Conclusion:
The emf produced at the secondary coil is 240V. Therefore, the correct answer is option B) 240V.
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An ideal transformer has 500 and the 1000 turns in the primary and the secondary coil. If the DC voltage of 120 V is applied to the primary coil, then the emf produced at the secondary coil will be:a)60 Vb)240 Vc)30 Vd)ZeroCorrect answer is option 'D'. Can you explain this answer?
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