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The average current of sinusoidly wearing alternate current of peak value 5 ampere with initial phase 0 between the instance t is equal to T / 8 to is equals toT/ 4?
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The average current of sinusoidly wearing alternate current of peak va...
Calculation of Average Current
- The average current of a sinusoidally varying alternating current can be calculated by taking the average value of the current over one complete cycle.
- The formula for calculating the average current is: I_avg = (1/T) * ∫(0 to T) i(t) dt, where T is the time period of the alternating current.

Given Parameters
- Peak value of alternating current, I_m = 5 A
- Initial phase, φ = 0
- We need to find the average current between the time instances t = T/8 and t = T/4.

Representation of Alternating Current
- The alternating current can be represented as: i(t) = I_m * sin(ωt + φ), where ω = 2π/T.

Calculation of Average Current between t = T/8 and t = T/4
- Substituting the given values into the formula for i(t), we get: i(t) = 5 * sin(2πt/T)
- To find the average current between t = T/8 and t = T/4, we need to calculate the average value of i(t) over this interval.
- The average current can be calculated as: I_avg = (1/(T/4 - T/8)) * ∫(T/8 to T/4) 5sin(2πt/T) dt
- After solving the integral, we get the average current value over this interval.

Conclusion
- By following the above steps, you can calculate the average current of a sinusoidally varying alternating current between two specific time instances.
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The average current of sinusoidly wearing alternate current of peak value 5 ampere with initial phase 0 between the instance t is equal to T / 8 to is equals toT/ 4?
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