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If log x to the base 2+log2 base x =10/3=log y base 2 +log 2 base y and x is not equal to y,then x+y =?
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If log x to the base 2+log2 base x =10/3=log y base 2 +log 2 base y an...
Given Information:
- log x to the base 2 + log2 base x = 10/3
- log y base 2 + log 2 base y = 10/3
- x is not equal to y

Calculation:
- Let's first simplify the given equations:
- log x to the base 2 + log2 base x = 10/3
- 2(log x) = 10/3
- log x = 5/3
- x = 2^(5/3) = 2^(1+2/3) = 2 * 2^(2/3)
- Similarly, for y:
- log y to the base 2 + log 2 base y = 10/3
- log y = 5/3
- y = 2^(5/3) = 2 * 2^(2/3)
- Since x is not equal to y, we can now find x + y:
- x + y = 2 * 2^(2/3) + 2 * 2^(2/3)
- x + y = 4 * 2^(2/3)
- x + y = 4 * ∛8
- x + y = 4 * 2 = 8

Final Answer:
- Therefore, x + y = 8.
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If log x to the base 2+log2 base x =10/3=log y base 2 +log 2 base y and x is not equal to y,then x+y =?
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