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2 square have sides 7 PCM and p + 5 cm the sum of the squares is 625 square CM the sides of the squares are?
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2 square have sides 7 PCM and p + 5 cm the sum of the squares is 625 s...
Given Information:
- Side of first square = 7 cm
- Side of second square = p + 5 cm
- Sum of the squares = 625 cm²

Let's solve the problem step by step:

Step 1: Express the sides of the squares as variables
Let the side of the first square be x cm and the side of the second square be y cm.
Given that x = 7 cm and y = p + 5 cm.

Step 2: Set up the equation
According to the given information, the sum of the squares is 625 cm².
Therefore, we can write the equation as: x² + y² = 625
Substitute the values of x and y into the equation:
(7)² + (p + 5)² = 625
49 + p² + 10p + 25 = 625
p² + 10p + 74 = 625

Step 3: Solve for p
Rearranging the equation:
p² + 10p - 551 = 0
(p + 29)(p - 19) = 0
p = -29 or p = 19

Step 4: Determine the sides of the squares
Using p = 19,
Side of the first square = 7 cm
Side of the second square = 19 + 5 = 24 cm
Therefore, the sides of the squares are:
First square: 7 cm
Second square: 24 cm

Conclusion:
The sides of the squares are 7 cm and 24 cm respectively.
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2 square have sides 7 PCM and p + 5 cm the sum of the squares is 625 square CM the sides of the squares are?
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