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Divide the 50 into two parts such that the sum of their recipes 1 by 12 the numbers are?
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Divide the 50 into two parts such that the sum of their recipes 1 by 1...



Step 1: Define the problem
To divide 50 into two parts such that the sum of their reciprocals is 1/12.

Step 2: Set up the equation
Let the two parts be x and 50-x. According to the problem, the equation can be set up as:
1/x + 1/(50-x) = 1/12

Step 3: Solve the equation
To solve the equation, first find a common denominator:
(50-x + x) / (x*(50-x)) = 1/12
50 / (x*(50-x)) = 1/12
600 = x*(50-x)
Now, solve the quadratic equation:
600 = 50x - x^2
x^2 - 50x + 600 = 0
(x-20)(x-30) = 0
Therefore, the two parts are 20 and 30.

Step 4: Verify the solution
To verify, substitute the values:
1/20 + 1/30 = 1/12
(3+2) / 60 = 1/12
5 / 60 = 1/12
1/12 = 1/12
Hence, the solution is correct.

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Divide the 50 into two parts such that the sum of their recipes 1 by 12 the numbers are?
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Divide the 50 into two parts such that the sum of their recipes 1 by 12 the numbers are? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Divide the 50 into two parts such that the sum of their recipes 1 by 12 the numbers are? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Divide the 50 into two parts such that the sum of their recipes 1 by 12 the numbers are?.
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