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There are two consecutive number such that the difference of the reciprocalci is one by 240 the numbers are option A 15 16 option to 17 option C 13 option d 12 13?
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There are two consecutive number such that the difference of the recip...
Consecutive Numbers with Reciprocal Difference
To solve this problem, we need to find two consecutive numbers whose reciprocals have a difference of 1/240.

Let the numbers be x and x+1
Given that the difference of their reciprocals is 1/240, we can set up the following equation:
1/x - 1/(x+1) = 1/240

Find a common denominator
To simplify the equation, we need to find a common denominator for the fractions on the left side. The common denominator in this case would be x(x+1).

Solve the equation
After finding a common denominator, we can rewrite the equation as follows:
(x+1 - x) / (x(x+1)) = 1/240
1 / (x(x+1)) = 1/240
Cross multiplying, we get:
x(x+1) = 240

Find the consecutive numbers
By solving the above equation, we get:
x^2 + x - 240 = 0
(x+16)(x-15) = 0
Therefore, the consecutive numbers are 15 and 16 (option A).

Conclusion
Thus, the two consecutive numbers whose reciprocals have a difference of 1/240 are 15 and 16.
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There are two consecutive number such that the difference of the reciprocalci is one by 240 the numbers are option A 15 16 option to 17 option C 13 option d 12 13?
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