UPSC Exam > UPSC Questions > A man moves on a straight path. He travels to...
Start Learning for Free
A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other half
of remaining time. Find the average speed in complete journey.?
of remaining time. Find the average speed in complete journey.?
Most Upvoted Answer
A man moves on a straight path. He travels total distance /. He travel...
Approach:
To find the average speed of the man in the complete journey, we need to consider the total distance traveled and the total time taken. We can break down the journey into different segments based on the speeds at which the man traveled.
1. First half of the journey (Speed 10 m/s):
- Distance covered = 1/2 total distance
- Speed = 10 m/s
- Time taken = Distance / Speed = (1/2 total distance) / 10 m/s = 1/20 total time
2. Second half of the journey (Speed 20 m/s for half time and 40 m/s for the other half):
- Distance covered = 1/2 total distance
- Speed = 20 m/s for 1/2 remaining time and 40 m/s for the other 1/2 remaining time
- Time taken = (1/2 total time) * 2 = total time
3. Calculating total time:
- Let total distance be D
- Total time = (1/20)D / 10 + (1/2)D / 20 + (1/2)D / 40
= D/200 + D/40 + D/80
= 8D/200 + 5D/200 + 2D/200
= 15D/200
= 3D/40
4. Calculating average speed:
- Total distance = D
- Total time = 3D/40
- Average speed = Total distance / Total time = D / (3D/40) = 40/3 m/s ≈ 13.33 m/s
Therefore, the average speed of the man in the complete journey is approximately 13.33 m/s.
To find the average speed of the man in the complete journey, we need to consider the total distance traveled and the total time taken. We can break down the journey into different segments based on the speeds at which the man traveled.
1. First half of the journey (Speed 10 m/s):
- Distance covered = 1/2 total distance
- Speed = 10 m/s
- Time taken = Distance / Speed = (1/2 total distance) / 10 m/s = 1/20 total time
2. Second half of the journey (Speed 20 m/s for half time and 40 m/s for the other half):
- Distance covered = 1/2 total distance
- Speed = 20 m/s for 1/2 remaining time and 40 m/s for the other 1/2 remaining time
- Time taken = (1/2 total time) * 2 = total time
3. Calculating total time:
- Let total distance be D
- Total time = (1/20)D / 10 + (1/2)D / 20 + (1/2)D / 40
= D/200 + D/40 + D/80
= 8D/200 + 5D/200 + 2D/200
= 15D/200
= 3D/40
4. Calculating average speed:
- Total distance = D
- Total time = 3D/40
- Average speed = Total distance / Total time = D / (3D/40) = 40/3 m/s ≈ 13.33 m/s
Therefore, the average speed of the man in the complete journey is approximately 13.33 m/s.
Attention UPSC Students!
To make sure you are not studying endlessly, EduRev has designed UPSC study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UPSC.
|
Explore Courses for UPSC exam
|
|
Similar UPSC Doubts
Top Courses for UPSCView all
A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.?
Question Description
A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.?.
A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.?.
Solutions for A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.? in English & in Hindi are available as part of our courses for UPSC.
Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.? defined & explained in the simplest way possible. Besides giving the explanation of
A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.?, a detailed solution for A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.? has been provided alongside types of A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.? theory, EduRev gives you an
ample number of questions to practice A man moves on a straight path. He travels total distance /. He travels half of his journey with speed 10 ms. The remaining part of journey was covered by him with speed 20 ms for half of remaining time and with velocity 40 ms for other halfof remaining time. Find the average speed in complete journey.? tests, examples and also practice UPSC tests.
|
|
Explore Courses for UPSC exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup