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The difference of two positive integer is 3 and the sum of their squares is 89. the integers are?
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The difference of two positive integer is 3 and the sum of their squar...
Given Information:
- Difference of two positive integers: 3
- Sum of their squares: 89

Finding the Integers:
1. Let's assume the two positive integers are x and y.
2. According to the given information, we can form two equations:
- x - y = 3 (equation 1)
- x^2 + y^2 = 89 (equation 2)
3. From equation 1, we can express x in terms of y as x = y + 3.
4. Substitute x = y + 3 into equation 2:
- (y + 3)^2 + y^2 = 89
- y^2 + 6y + 9 + y^2 = 89
- 2y^2 + 6y - 80 = 0
- y^2 + 3y - 40 = 0
- (y + 8)(y - 5) = 0
5. So, the possible values for y are 5 and -8. Since the integers are positive, y = 5.
6. Substitute y = 5 back into x = y + 3 to find x:
- x = 5 + 3
- x = 8

Therefore, the two positive integers are:
- x = 8
- y = 5
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The difference of two positive integer is 3 and the sum of their squares is 89. the integers are?
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