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8829 is invested into 3 different sectors in such a way that the amounts at 4% p.a S.I after 5 years,6 years, 8years is equal.find the amount of sum?
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8829 is invested into 3 different sectors in such a way that the amoun...
Given information:
- Total amount invested: $8829
- Rate of interest: 4% p.a
- Time period: 5 years, 6 years, 8 years
Let x, y, z be the amounts invested in each sector.
Formulas:
- Simple Interest (SI) = P * R * T / 100
- Total amount = x + y + z
Calculations:
Amount after 5 years:
- SI1 = x * 4 * 5 / 100
- SI2 = y * 4 * 5 / 100
- SI3 = z * 4 * 5 / 100
Amount after 6 years:
- SI4 = x * 4 * 6 / 100
- SI5 = y * 4 * 6 / 100
- SI6 = z * 4 * 6 / 100
Amount after 8 years:
- SI7 = x * 4 * 8 / 100
- SI8 = y * 4 * 8 / 100
- SI9 = z * 4 * 8 / 100
Given that the amounts at 5, 6, and 8 years are equal:
- SI1 + SI4 + SI7 = SI2 + SI5 + SI8 = SI3 + SI6 + SI9
Substitute the respective values:
- x * 4 * 5 / 100 + x * 4 * 6 / 100 + x * 4 * 8 / 100 = y * 4 * 5 / 100 + y * 4 * 6 / 100 + y * 4 * 8 / 100 = z * 4 * 5 / 100 + z * 4 * 6 / 100 + z * 4 * 8 / 100
Solve the equation:
- 20x + 24x + 32x = 20y + 24y + 32y = 20z + 24z + 32z
- 76x = 76y = 76z
- x = y = z = $2943
Therefore, the amount invested in each sector is $2943.
- Total amount invested: $8829
- Rate of interest: 4% p.a
- Time period: 5 years, 6 years, 8 years
Let x, y, z be the amounts invested in each sector.
Formulas:
- Simple Interest (SI) = P * R * T / 100
- Total amount = x + y + z
Calculations:
Amount after 5 years:
- SI1 = x * 4 * 5 / 100
- SI2 = y * 4 * 5 / 100
- SI3 = z * 4 * 5 / 100
Amount after 6 years:
- SI4 = x * 4 * 6 / 100
- SI5 = y * 4 * 6 / 100
- SI6 = z * 4 * 6 / 100
Amount after 8 years:
- SI7 = x * 4 * 8 / 100
- SI8 = y * 4 * 8 / 100
- SI9 = z * 4 * 8 / 100
Given that the amounts at 5, 6, and 8 years are equal:
- SI1 + SI4 + SI7 = SI2 + SI5 + SI8 = SI3 + SI6 + SI9
Substitute the respective values:
- x * 4 * 5 / 100 + x * 4 * 6 / 100 + x * 4 * 8 / 100 = y * 4 * 5 / 100 + y * 4 * 6 / 100 + y * 4 * 8 / 100 = z * 4 * 5 / 100 + z * 4 * 6 / 100 + z * 4 * 8 / 100
Solve the equation:
- 20x + 24x + 32x = 20y + 24y + 32y = 20z + 24z + 32z
- 76x = 76y = 76z
- x = y = z = $2943
Therefore, the amount invested in each sector is $2943.
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8829 is invested into 3 different sectors in such a way that the amounts at 4% p.a S.I after 5 years,6 years, 8years is equal.find the amount of sum?
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8829 is invested into 3 different sectors in such a way that the amounts at 4% p.a S.I after 5 years,6 years, 8years is equal.find the amount of sum? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 8829 is invested into 3 different sectors in such a way that the amounts at 4% p.a S.I after 5 years,6 years, 8years is equal.find the amount of sum? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 8829 is invested into 3 different sectors in such a way that the amounts at 4% p.a S.I after 5 years,6 years, 8years is equal.find the amount of sum?.
8829 is invested into 3 different sectors in such a way that the amounts at 4% p.a S.I after 5 years,6 years, 8years is equal.find the amount of sum? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 8829 is invested into 3 different sectors in such a way that the amounts at 4% p.a S.I after 5 years,6 years, 8years is equal.find the amount of sum? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 8829 is invested into 3 different sectors in such a way that the amounts at 4% p.a S.I after 5 years,6 years, 8years is equal.find the amount of sum?.
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