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The 3rd term of arithmetic progression is 7 and the 7 term is 15.find the comman difference and the first term.?
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The 3rd term of arithmetic progression is 7 and the 7 term is 15.find ...
Given information:
- 3rd term (a3) = 7
- 7th term (a7) = 15

Finding the common difference (d):
- Using the formula for the nth term of an arithmetic progression: an = a1 + (n-1)d
- Substituting the given values, we get:
a3 = a1 + 2d (since n=3)
a7 = a1 + 6d (since n=7)
- From the given data, we have a3 = 7 and a7 = 15
- Substituting these values, we get:
7 = a1 + 2d
15 = a1 + 6d
- Subtracting the first equation from the second, we get:
15 - 7 = 6d - 2d
8 = 4d
d = 2

Finding the first term (a1):
- Using the formula for the nth term of an arithmetic progression: an = a1 + (n-1)d
- Substituting the values of a3 and d, we get:
7 = a1 + 2(2)
7 = a1 + 4
a1 = 3

Conclusion:
- The common difference (d) is 2
- The first term (a1) is 3.
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The 3rd term of arithmetic progression is 7 and the 7 term is 15.find the comman difference and the first term.?
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