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The numbers x, 8, y  are in G.P. and the numbers x, y, –8 are in A.P. The value of x and y are
  • a)
    (–8, –8)
  • b)
    (16, 4)
  • c)
    (8, 8)
  • d)
    none of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The numbers x, 8, y are in G.P. and the numbers x, y, –8 are in ...
So for a GP a,b,c we have b = √ac

and a AP A,B,C We have 2B = A + C

so here 

x,8,y is in GP   so 8 = √xy  ⇒ 64/x = y .  ....  i

and x,y,-8 in AP   so 2y = x - 8               .... ii

using i and ii

we get

128/x = x - 8

⇒ 128 = x^2 - 8x

⇒ x^2  - 8x - 128 = 0

⇒ x^2 - 16x + 8x - 128 = 0

⇒ x(x - 16) + 8(x - 16) = 0

⇒(x - 16)(x + 8) = 0


so x = 16 or - 8

so y = 4 or -8

so the GP is 16,8,4  but -8,8,-8 is not possible

and for the AP 

16,8,-8 again -8,-8,-8 is not possible 

so values fo x = 16 and y = 4
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Most Upvoted Answer
The numbers x, 8, y are in G.P. and the numbers x, y, –8 are in ...
Given: x, 8, y are in G.P. and x, y, 8 are in A.P.

To find: Value of x and y

Solution:

Let the common ratio of the G.P. be r.

Then, according to the given information, we have:

y = 8r

and

x/y = r

=> x = ry

Also, x, y, 8 are in A.P.

So, we have:

y - x = x - 8

=> y - ry = ry - 8

=> y(1 - r) = 8(1 - r)

=> y = 8

=> x = ry = r(8) = 8r = 4

Therefore, the value of x and y is (4, 8).

Hence, option B is the correct answer.
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Community Answer
The numbers x, 8, y are in G.P. and the numbers x, y, –8 are in ...
Ans is b I think option a in ap d is 0 ap difference doesn't come in 0 and c option also same that so option is c
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The numbers x, 8, y are in G.P. and the numbers x, y, –8 are in A.P. The value of x and y area)(–8, –8)b)(16, 4)c)(8, 8)d)none of theseCorrect answer is option 'B'. Can you explain this answer?
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