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Drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:?
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Drunkard is walking along a straight road. He takes 5 steps forward an...
Analysis:
The drunkard's movement can be represented as a series of steps forward and backward along a straight line. Each step is 1 meter long and takes 1 second to complete. The drunkard takes 5 steps forward and 3 steps backward repeatedly.
Distance from Starting Point:
After every cycle of 5 steps forward and 3 steps backward, the drunkard's net displacement is 2 meters forward. This means that after n cycles, the drunkard will be n*2 meters away from the starting point.
Falling into the Pit:
Given that the pit is 11 meters away from the starting point, the drunkard will fall into the pit when the distance between him and the pit is less than 2 meters, which is the net displacement after one cycle.
Calculation:
Let's calculate the number of cycles needed for the drunkard to fall into the pit:
Distance to the pit = 11 meters
Net displacement per cycle = 2 meters
Number of cycles = Distance to the pit / Net displacement per cycle
Number of cycles = 11 meters / 2 meters
Number of cycles = 5.5 cycles
Since the drunkard cannot complete a fraction of a cycle, he will fall into the pit after completing 5 cycles.
Conclusion:
Therefore, the drunkard will fall into the pit after completing 5 cycles of 5 steps forward and 3 steps backward. This means he will fall into the pit after taking 40 steps in total.
The drunkard's movement can be represented as a series of steps forward and backward along a straight line. Each step is 1 meter long and takes 1 second to complete. The drunkard takes 5 steps forward and 3 steps backward repeatedly.
Distance from Starting Point:
After every cycle of 5 steps forward and 3 steps backward, the drunkard's net displacement is 2 meters forward. This means that after n cycles, the drunkard will be n*2 meters away from the starting point.
Falling into the Pit:
Given that the pit is 11 meters away from the starting point, the drunkard will fall into the pit when the distance between him and the pit is less than 2 meters, which is the net displacement after one cycle.
Calculation:
Let's calculate the number of cycles needed for the drunkard to fall into the pit:
Distance to the pit = 11 meters
Net displacement per cycle = 2 meters
Number of cycles = Distance to the pit / Net displacement per cycle
Number of cycles = 11 meters / 2 meters
Number of cycles = 5.5 cycles
Since the drunkard cannot complete a fraction of a cycle, he will fall into the pit after completing 5 cycles.
Conclusion:
Therefore, the drunkard will fall into the pit after completing 5 cycles of 5 steps forward and 3 steps backward. This means he will fall into the pit after taking 40 steps in total.
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Drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:?
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Drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:?.
Drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after:?.
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