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10g of limestone on heating produces 4.2g of CaO. the percentage purity of CaCO3 in limestone is:

  • a)
    50%

  • b)
    72%

  • c)
    75 %

  • d)
    100%

Correct answer is option 'C'. Can you explain this answer?
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Calculation of Percentage Yield of CaCO3 Reaction

Given:

- Mass of CaCO3 = 10 g
- Mass of residue (as CaO) = 5 g

To calculate the percentage yield of the reaction, we need to use the formula:

Percentage Yield = (Actual Yield / Theoretical Yield) × 100

Where:

- Actual Yield = the amount of product obtained from the reaction
- Theoretical Yield = the maximum amount of product that can be obtained from the reaction, based on the stoichiometry of the reaction

Step 1: Calculate the Theoretical Yield of CaO

The balanced chemical equation for the reaction between CaCO3 and heat is:

CaCO3(s) → CaO(s) + CO2(g)

From the equation, we can see that:

- 1 mole of CaCO3 produces 1 mole of CaO
- The molar mass of CaCO3 is 100.09 g/mol
- The molar mass of CaO is 56.08 g/mol

Therefore, the theoretical yield of CaO can be calculated as:

Theoretical Yield of CaO = (10 g / 100.09 g/mol) × 56.08 g/mol = 5.586 g

Step 2: Calculate the Actual Yield of CaO

The mass of residue obtained in the reaction is 5 g, which is the actual yield of CaO.

Actual Yield of CaO = 5 g

Step 3: Calculate the Percentage Yield of the Reaction

Using the formula for percentage yield, we can calculate:

Percentage Yield = (Actual Yield / Theoretical Yield) × 100 = (5 g / 5.586 g) × 100 = 89.56%

Therefore, the percentage yield of the reaction between CaCO3 and heat is approximately 89%.
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10gof limestone on heating produces4.2gofCaO. the percentage purity ofCaCO3in limestone is:a)50%b)72%c)75 %d)100%Correct answer is option 'C'. Can you explain this answer?
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