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If h(x)=5x²+2x+1,find the value of each of the following
(1)h(2x)
(2)h(x+1)
(3)h(x+1)-h(x-1)?
Most Upvoted Answer
If h(x)=5x²+2x+1,find the value of each of the following (1)h(2x)(2)h(...
h(x)=5x²+2x+1

1. h(2x)
When finding h(2x), we substitute 2x in place of x in the given function h(x):
h(2x) = 5(2x)² + 2(2x) + 1
= 5(4x²) + 4x + 1
= 20x² + 4x + 1
Therefore, h(2x) = 20x² + 4x + 1.

2. h(x+1)
To find h(x+1), we substitute x+1 in place of x in the function h(x):
h(x+1) = 5(x+1)² + 2(x+1) + 1
= 5(x²+2x+1) + 2x + 2 + 1
= 5x² + 10x + 5 + 2x + 3
= 5x² + 12x + 8
Therefore, h(x+1) = 5x² + 12x + 8.

3. h(x+1) - h(x-1)
To find h(x+1) - h(x-1), we first calculate h(x+1) as 5x² + 12x + 8 and h(x-1) as 5x² - 12x + 6. Then, we subtract h(x-1) from h(x+1):
(5x² + 12x + 8) - (5x² - 12x + 6)
= 5x² + 12x + 8 - 5x² + 12x - 6
= 24x + 2
Therefore, h(x+1) - h(x-1) = 24x + 2.
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If h(x)=5x²+2x+1,find the value of each of the following (1)h(2x)(2)h(x+1)(3)h(x+1)-h(x-1)?
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