If any two letters in the word 'PRISON' have as many letters b...
To find the alpha-pairs in the word PRISON, we need to check if any two letters have exactly 26 letters between them in the English alphabet.
- P and N: There are 14 letters between P and N in the English alphabet, so they do not form an alpha-pair.
- P and R: There are 16 letters between P and R in the English alphabet, so they do not form an alpha-pair.
- P and I: There are 8 letters between P and I in the English alphabet, so they do not form an alpha-pair.
- P and S: There are 18 letters between P and S in the English alphabet, so they do not form an alpha-pair.
- P and O: There are 15 letters between P and O in the English alphabet, so they do not form an alpha-pair.
- R and N: There are 13 letters between R and N in the English alphabet, so they do not form an alpha-pair.
- R and I: There are 7 letters between R and I in the English alphabet, so they do not form an alpha-pair.
- R and S: There are 17 letters between R and S in the English alphabet, so they do not form an alpha-pair.
- R and O: There are 14 letters between R and O in the English alphabet, so they do not form an alpha-pair.
- I and N: There are 12 letters between I and N in the English alphabet, so they do not form an alpha-pair.
- I and S: There are 10 letters between I and S in the English alphabet, so they do not form an alpha-pair.
- I and O: There are 9 letters between I and O in the English alphabet, so they do not form an alpha-pair.
- S and N: There are 12 letters between S and N in the English alphabet, so they do not form an alpha-pair.
- S and O: There are 8 letters between S and O in the English alphabet, so they do not form an alpha-pair.
- O and N: There are 13 letters between O and N in the English alphabet, so they do not form an alpha-pair.
Therefore, there are no alpha-pairs in the word PRISON. The answer is (a) Nil.
If any two letters in the word 'PRISON' have as many letters b...
Yes correct answer will be 'E'
1st pair 'PS'
2nd pair 'NO'
3rd pair 'NR'
4th pair 'OR'