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A number when divided by a certain divisor leaves remainder 47 when twice of the number is divided the same devices the remainder is 36 the divisor is?
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A number when divided by a certain divisor leaves remainder 47 when tw...


Given information:

- Remainder when number is divided by divisor = 47
- Remainder when twice of the number is divided by same divisor = 36
Solution:

Let's assume:

- Number = x
- Divisor = d
First condition:

When x is divided by d, remainder is 47.
So, x = qd + 47, where q is the quotient.
Second condition:

When 2x is divided by d, remainder is 36.
So, 2x = pd + 36, where p is the quotient.
Substitute x in the second condition:

2(qd + 47) = pd + 36
2qd + 94 = pd + 36
2qd - pd = 36 - 94
qd = -58
Therefore, the divisor is:

d = -58/q
Conclusion:

The divisor is -58/q.
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A number when divided by a certain divisor leaves remainder 47 when twice of the number is divided the same devices the remainder is 36 the divisor is?
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