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An object is submerged in water. The level of the water changes from 100 ml to 180 ml. Mass of the object is 250 g. Take density of water = 0.998 g/cc and g=9.8 m.s². Find the density of the object. Find the buoyancy on the object.?
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An object is submerged in water. The level of the water changes from 1...
Calculating Density of the Object:
1. First, calculate the volume of the object submerged in water:
Initial volume of water = 100 ml = 100 cm³
Final volume of water = 180 ml = 180 cm³
Volume of object submerged = Final volume - Initial volume = 180 cm³ - 100 cm³ = 80 cm³
2. Calculate the density of water:
Density of water = 0.998 g/cm³
3. Now, use the formula for density:
Density = Mass / Volume
Density of the object = Mass of object / Volume of object submerged
Density of the object = 250 g / 80 cm³ ≈ 3.125 g/cm³
Calculating Buoyancy on the Object:
1. Buoyant force is the force exerted by a fluid that opposes the weight of an immersed object. It can be calculated using the formula:
Buoyant force = Density of fluid x Volume of fluid displaced x g
2. Calculate the volume of fluid displaced:
Volume of fluid displaced = Final volume - Initial volume = 180 cm³ - 100 cm³ = 80 cm³
3. Now, calculate the buoyant force acting on the object:
Buoyant force = 0.998 g/cm³ x 80 cm³ x 9.8 m/s² ≈ 783.04 g.m/s²
Therefore, the density of the object is approximately 3.125 g/cm³ and the buoyant force acting on the object is approximately 783.04 g.m/s².
1. First, calculate the volume of the object submerged in water:
Initial volume of water = 100 ml = 100 cm³
Final volume of water = 180 ml = 180 cm³
Volume of object submerged = Final volume - Initial volume = 180 cm³ - 100 cm³ = 80 cm³
2. Calculate the density of water:
Density of water = 0.998 g/cm³
3. Now, use the formula for density:
Density = Mass / Volume
Density of the object = Mass of object / Volume of object submerged
Density of the object = 250 g / 80 cm³ ≈ 3.125 g/cm³
Calculating Buoyancy on the Object:
1. Buoyant force is the force exerted by a fluid that opposes the weight of an immersed object. It can be calculated using the formula:
Buoyant force = Density of fluid x Volume of fluid displaced x g
2. Calculate the volume of fluid displaced:
Volume of fluid displaced = Final volume - Initial volume = 180 cm³ - 100 cm³ = 80 cm³
3. Now, calculate the buoyant force acting on the object:
Buoyant force = 0.998 g/cm³ x 80 cm³ x 9.8 m/s² ≈ 783.04 g.m/s²
Therefore, the density of the object is approximately 3.125 g/cm³ and the buoyant force acting on the object is approximately 783.04 g.m/s².
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An object is submerged in water. The level of the water changes from 100 ml to 180 ml. Mass of the object is 250 g. Take density of water = 0.998 g/cc and g=9.8 m.s². Find the density of the object. Find the buoyancy on the object.?
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An object is submerged in water. The level of the water changes from 100 ml to 180 ml. Mass of the object is 250 g. Take density of water = 0.998 g/cc and g=9.8 m.s². Find the density of the object. Find the buoyancy on the object.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about An object is submerged in water. The level of the water changes from 100 ml to 180 ml. Mass of the object is 250 g. Take density of water = 0.998 g/cc and g=9.8 m.s². Find the density of the object. Find the buoyancy on the object.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is submerged in water. The level of the water changes from 100 ml to 180 ml. Mass of the object is 250 g. Take density of water = 0.998 g/cc and g=9.8 m.s². Find the density of the object. Find the buoyancy on the object.?.
An object is submerged in water. The level of the water changes from 100 ml to 180 ml. Mass of the object is 250 g. Take density of water = 0.998 g/cc and g=9.8 m.s². Find the density of the object. Find the buoyancy on the object.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about An object is submerged in water. The level of the water changes from 100 ml to 180 ml. Mass of the object is 250 g. Take density of water = 0.998 g/cc and g=9.8 m.s². Find the density of the object. Find the buoyancy on the object.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is submerged in water. The level of the water changes from 100 ml to 180 ml. Mass of the object is 250 g. Take density of water = 0.998 g/cc and g=9.8 m.s². Find the density of the object. Find the buoyancy on the object.?.
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