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If numerator of a fraction increased by 1 its value changes to 1/2 and the denominator is increased by one the value change to 1/3. The fraction is?
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If numerator of a fraction increased by 1 its value changes to 1/2 and...
Solution:

Given:
Let the original fraction be x/y.

First condition:
When the numerator is increased by 1, the fraction becomes (x+1)/y = 1/2.

Second condition:
When the denominator is increased by 1, the fraction becomes x/(y+1) = 1/3.

Solving the first condition:
(x+1)/y = 1/2
x+1 = y/2
x = y/2 - 1

Solving the second condition:
x/(y+1) = 1/3
x = (y+1)/3

Equating the two expressions for x:
y/2 - 1 = (y+1)/3
3y - 6 = 2y + 2
y = 8

Substitute y back into x:
x = 8/2 - 1
x = 3
Therefore, the original fraction is 3/8.
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If numerator of a fraction increased by 1 its value changes to 1/2 and the denominator is increased by one the value change to 1/3. The fraction is?
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