Counting Three-Digit Numbers
To determine how many three-digit numbers can be repeated using the digits 5, 6, 7, 8, 9, we need to consider the number of options for each digit position.

First Digit Options
For the hundreds place, we have 5 options (5, 6, 7, 8, 9) since we cannot have a leading zero in a three-digit number.

Second Digit Options
For the tens place, we can repeat any of the 5 digits (5, 6, 7, 8, 9), including the one already used in the hundreds place. So, there are 5 options for the second digit.

Third Digit Options
Similarly, for the units place, we can repeat any of the 5 digits (5, 6, 7, 8, 9), including those already used in the hundreds and tens places. So, there are 5 options for the third digit.

Total Number of Three-Digit Numbers
To find the total number of three-digit numbers that can be formed using the digits 5, 6, 7, 8, 9, we multiply the number of options for each digit position.
Therefore, the total number of three-digit numbers that can be repeated is:
5 (options for the hundreds place) x 5 (options for the tens place) x 5 (options for the units place) = 125.
Hence, there are 125 three-digit numbers that can be repeated using the digits 5, 6, 7, 8, 9.