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The minute and of a clock is 12 CM long find the area on the face of the clock described by the minute and in 35 minutes?
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The minute and of a clock is 12 CM long find the area on the face of t...
- Area of the Minute Hand in 35 minutes
The area covered by the minute hand of a clock in a certain time period can be calculated by finding the angle swept by the minute hand in that time period and then finding the area of the sector formed by that angle.
- Angle swept by the Minute Hand
Since the minute hand covers 360 degrees in 60 minutes, in 35 minutes it will cover an angle of (35/60) * 360 = 210 degrees.
- Area of the Sector
Now, the area of the sector formed by the minute hand can be calculated using the formula:
Area = (θ/360) * π * r^2
where θ is the angle swept by the minute hand, π is a constant (3.14), and r is the length of the minute hand (12 cm).
- Substituting the values
In this case, the angle swept is 210 degrees, the radius is 12 cm, and π is approximately 3.14. So, substituting these values into the formula, we get:
Area = (210/360) * 3.14 * 12^2
Area = (7/12) * 3.14 * 144
Area = (7/12) * 452.16
Area ≈ 263.08 square centimeters
- Conclusion
Therefore, the area covered by the minute hand of the clock in 35 minutes is approximately 263.08 square centimeters.
The area covered by the minute hand of a clock in a certain time period can be calculated by finding the angle swept by the minute hand in that time period and then finding the area of the sector formed by that angle.
- Angle swept by the Minute Hand
Since the minute hand covers 360 degrees in 60 minutes, in 35 minutes it will cover an angle of (35/60) * 360 = 210 degrees.
- Area of the Sector
Now, the area of the sector formed by the minute hand can be calculated using the formula:
Area = (θ/360) * π * r^2
where θ is the angle swept by the minute hand, π is a constant (3.14), and r is the length of the minute hand (12 cm).
- Substituting the values
In this case, the angle swept is 210 degrees, the radius is 12 cm, and π is approximately 3.14. So, substituting these values into the formula, we get:
Area = (210/360) * 3.14 * 12^2
Area = (7/12) * 3.14 * 144
Area = (7/12) * 452.16
Area ≈ 263.08 square centimeters
- Conclusion
Therefore, the area covered by the minute hand of the clock in 35 minutes is approximately 263.08 square centimeters.
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The minute and of a clock is 12 CM long find the area on the face of the clock described by the minute and in 35 minutes?
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The minute and of a clock is 12 CM long find the area on the face of the clock described by the minute and in 35 minutes? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about The minute and of a clock is 12 CM long find the area on the face of the clock described by the minute and in 35 minutes? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The minute and of a clock is 12 CM long find the area on the face of the clock described by the minute and in 35 minutes?.
The minute and of a clock is 12 CM long find the area on the face of the clock described by the minute and in 35 minutes? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about The minute and of a clock is 12 CM long find the area on the face of the clock described by the minute and in 35 minutes? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The minute and of a clock is 12 CM long find the area on the face of the clock described by the minute and in 35 minutes?.
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