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Seema has joined a new Company after the completion of her B.Tech from a reputed engineering college in Chennai. She saves 10% of her income in each of the first three months of her service and for every subsequent month, her savings are Rs. 50 more than the savings of the immediate previous month. If her joining income was Rs. 3000, her total savings from the start of the service will be Rs. 11400 in how many months?
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Seema has joined a new Company after the completion of her B.Tech from...
Given Information:
- Seema saves 10% of her income in the first three months and then increases her savings by Rs. 50 each subsequent month.
- Seema's joining income was Rs. 3000.
- Her total savings from the start of the service will be Rs. 11400.

Calculating Seema's Monthly Savings:
- Seema saves 10% of her income in the first three months: 10% of Rs. 3000 = Rs. 300
- Let's assume the savings for the fourth month is x.
- Therefore, Seema's savings for the fourth month will be Rs. 300 + Rs. 50 = Rs. 350
- For the fifth month, Seema's savings will be x + Rs. 50 = x + Rs. 50 + Rs. 50 = x + Rs. 100
- Similarly, for the sixth month, her savings will be x + Rs. 150
- In general, for the nth month, her savings will be x + (n-3) * Rs. 50

Calculating the Total Savings:
- The total savings from the start of the service will be the sum of all her savings for each month.
- Total savings = Rs. 300 + Rs. 300 + Rs. 300 + (x + Rs. 50) + (x + Rs. 100) + (x + Rs. 150) + ...
- Total savings = 3 * Rs. 300 + x + (x + Rs. 50) + (x + Rs. 100) + ... = Rs. 900 + nx + (1 + 2 + ... + n-3) * Rs. 50
- Total savings = Rs. 900 + nx + (n-3)(n-2)/2 * Rs. 50

Solving for n:
- Given that the total savings are Rs. 11400, we can equate the equation to 11400 and solve for n.
- Rs. 11400 = Rs. 900 + nx + (n-3)(n-2)/2 * Rs. 50
- Rs. 11400 = Rs. 900 + nx + (n^2 - 5n + 6) * Rs. 25
- 25n^2 - 125n + 150 + 9000 = 0
- 25n^2 - 125n - 9000 = 0
- n^2 - 5n - 360 = 0
- (n - 20)(n + 15) = 0
- n = 20 (ignoring negative value)
Therefore, Seema's total savings will be Rs. 11400 in 20 months.
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Seema has joined a new Company after the completion of her B.Tech from a reputed engineering college in Chennai. She saves 10% of her income in each of the first three months of her service and for every subsequent month, her savings are Rs. 50 more than the savings of the immediate previous month. If her joining income was Rs. 3000, her total savings from the start of the service will be Rs. 11400 in how many months?
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Seema has joined a new Company after the completion of her B.Tech from a reputed engineering college in Chennai. She saves 10% of her income in each of the first three months of her service and for every subsequent month, her savings are Rs. 50 more than the savings of the immediate previous month. If her joining income was Rs. 3000, her total savings from the start of the service will be Rs. 11400 in how many months? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Seema has joined a new Company after the completion of her B.Tech from a reputed engineering college in Chennai. She saves 10% of her income in each of the first three months of her service and for every subsequent month, her savings are Rs. 50 more than the savings of the immediate previous month. If her joining income was Rs. 3000, her total savings from the start of the service will be Rs. 11400 in how many months? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Seema has joined a new Company after the completion of her B.Tech from a reputed engineering college in Chennai. She saves 10% of her income in each of the first three months of her service and for every subsequent month, her savings are Rs. 50 more than the savings of the immediate previous month. If her joining income was Rs. 3000, her total savings from the start of the service will be Rs. 11400 in how many months?.
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