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[cr(en)2Cl2]cl may be found in two forms, one is violet and other is green. on reaction with oxalate ion the violet Species produces its corresponding oxalate derivative, while the green does not. Explain the result.?
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[cr(en)2Cl2]cl may be found in two forms, one is violet and other is g...
Explanation:
Two Forms of [Cr(en)2Cl2]Cl:
- The violet form of [Cr(en)2Cl2]Cl is a low-spin species with a d^3 electron configuration, while the green form is a high-spin species with a d^4 electron configuration.
Reaction with Oxalate Ion:
- The violet species with a low-spin configuration can undergo a ligand exchange reaction with oxalate ions to form its corresponding oxalate derivative.
- The green species with a high-spin configuration does not undergo the ligand exchange reaction with oxalate ions.
Reason for the Difference:
- The difference in reactivity towards oxalate ions is due to the electronic configuration of the two forms of [Cr(en)2Cl2]Cl.
- The low-spin violet species has a more stable electron configuration that allows for the ligand exchange reaction to occur.
- The high-spin green species is less stable and does not undergo the ligand exchange reaction with oxalate ions.
Conclusion:
- The difference in color and reactivity of the two forms of [Cr(en)2Cl2]Cl towards oxalate ions is a result of their electronic configurations. The violet species with a low-spin configuration is able to form its oxalate derivative, while the green species with a high-spin configuration does not undergo the same reaction.
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[cr(en)2Cl2]cl may be found in two forms, one is violet and other is green. on reaction with oxalate ion the violet Species produces its corresponding oxalate derivative, while the green does not. Explain the result.?
Question Description
[cr(en)2Cl2]cl may be found in two forms, one is violet and other is green. on reaction with oxalate ion the violet Species produces its corresponding oxalate derivative, while the green does not. Explain the result.? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about [cr(en)2Cl2]cl may be found in two forms, one is violet and other is green. on reaction with oxalate ion the violet Species produces its corresponding oxalate derivative, while the green does not. Explain the result.? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for [cr(en)2Cl2]cl may be found in two forms, one is violet and other is green. on reaction with oxalate ion the violet Species produces its corresponding oxalate derivative, while the green does not. Explain the result.?.
[cr(en)2Cl2]cl may be found in two forms, one is violet and other is green. on reaction with oxalate ion the violet Species produces its corresponding oxalate derivative, while the green does not. Explain the result.? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about [cr(en)2Cl2]cl may be found in two forms, one is violet and other is green. on reaction with oxalate ion the violet Species produces its corresponding oxalate derivative, while the green does not. Explain the result.? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for [cr(en)2Cl2]cl may be found in two forms, one is violet and other is green. on reaction with oxalate ion the violet Species produces its corresponding oxalate derivative, while the green does not. Explain the result.?.
Solutions for [cr(en)2Cl2]cl may be found in two forms, one is violet and other is green. on reaction with oxalate ion the violet Species produces its corresponding oxalate derivative, while the green does not. Explain the result.? in English & in Hindi are available as part of our courses for Chemistry.
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