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A number consists of two digits. The digits in the ten's place is 3 times the digit in the unit's place. If 54 is subtracted from the number the digits are reversed. The number is
a) 39
b) 92
c) 93
d) 94?
Most Upvoted Answer
A number consists of two digits. The digits in the ten's place is 3 ti...
Given Information:
- The number consists of two digits.
- The digit in the ten's place is 3 times the digit in the unit's place.
- When 54 is subtracted from the number, the digits are reversed.

Let's assume the number:
- Let the digit in the ten's place be x.
- Let the digit in the unit's place be y.

Formulating the Number:
- The number can be represented as 10x + y.

Given Conditions:
1. x = 3y (The digit in the ten's place is 3 times the digit in the unit's place)
2. When 54 is subtracted from the number, the digits are reversed:
- (10x + y) - 54 = 10y + x

Solving the Equations:
- Substituting x = 3y into the second equation:
10(3y) + y - 54 = 10y + 3y
30y + y - 54 = 13y
31y - 54 = 13y
18y = 54
y = 3
- Substituting y = 3 back into x = 3y:
x = 3(3)
x = 9

Final Number:
- The number is 10x + y = 10(9) + 3 = 90 + 3 = 93.
Therefore, the number is 93 (option c).
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A number consists of two digits. The digits in the ten's place is 3 times the digit in the unit's place. If 54 is subtracted from the number the digits are reversed. The number isa) 39b) 92c) 93d) 94?
Question Description
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