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Triangle ABC, right angled at C, then the value of cosec (A + B) is?
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Triangle ABC, right angled at C, then the value of cosec (A + B) is?
Given Information:
- Triangle ABC is right-angled at C.

To find:
The value of cosec(A + B).

Explanation:

Step 1: Finding the values of angles A, B, and C:
- In a right-angled triangle, angle C is 90 degrees.
- Since the sum of angles in a triangle is 180 degrees, we can find the values of angles A and B.
- Therefore, A + B + 90 = 180
- A + B = 90

Step 2: Finding the value of cosec(A + B):
- We know that cosec(x) = 1/sin(x).
- Therefore, cosec(A + B) = 1/sin(A + B).

Step 3: Finding the value of sin(A + B):
- Using the trigonometric identity sin(A + B) = sinAcosB + cosAsinB.
- In this case, since A + B = 90 degrees, sin(A + B) = sin90 = 1.

Step 4: Finding the value of cosec(A + B):
- Therefore, cosec(A + B) = 1/sin(A + B) = 1/1 = 1.

Conclusion:
- The value of cosec(A + B) in a right-angled triangle ABC is 1.
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Triangle ABC, right angled at C, then the value of cosec (A + B) is?
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