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The sum of the first n terms of the series 1 ^ 2 + 2.2 ^ 2 + 3 ^ 2 + 2.4 ^ 2 + 5 ^ 2 + 2.6 ^ 2 +... is (n * (n + 1) ^ 2)/2 even. When n is odd the sum is?
Most Upvoted Answer
The sum of the first n terms of the series 1 ^ 2 + 2.2 ^ 2 + 3 ^ 2 + 2...
Explanation:

Given Series:
1 ^ 2 + 2.2 ^ 2 + 3 ^ 2 + 2.4 ^ 2 + 5 ^ 2 + 2.6 ^ 2 +...

Sum of the First n Terms:
The sum of the first n terms of the series is given by the formula: (n * (n + 1) ^ 2) / 2

When n is Odd:
When n is odd, the sum of the first n terms can be calculated using the formula above. Let's consider n = 3 as an example:
Sum = (3 * (3 + 1) ^ 2) / 2
Sum = (3 * 4 ^ 2) / 2
Sum = (3 * 16) / 2
Sum = 48 / 2
Sum = 24
Therefore, when n is odd, the sum of the first n terms will be an even number, as shown in the example above.

Explanation:
- The sum of the first n terms of the series is given by the formula: (n * (n + 1) ^ 2) / 2
- When n is odd, the sum will always be an even number.
- This is because the product of an odd number and any number (odd or even) is always even.
- Thus, the sum of the first n terms of the series will be an even number when n is odd.
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The sum of the first n terms of the series 1 ^ 2 + 2.2 ^ 2 + 3 ^ 2 + 2.4 ^ 2 + 5 ^ 2 + 2.6 ^ 2 +... is (n * (n + 1) ^ 2)/2 even. When n is odd the sum is?
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The sum of the first n terms of the series 1 ^ 2 + 2.2 ^ 2 + 3 ^ 2 + 2.4 ^ 2 + 5 ^ 2 + 2.6 ^ 2 +... is (n * (n + 1) ^ 2)/2 even. When n is odd the sum is? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about The sum of the first n terms of the series 1 ^ 2 + 2.2 ^ 2 + 3 ^ 2 + 2.4 ^ 2 + 5 ^ 2 + 2.6 ^ 2 +... is (n * (n + 1) ^ 2)/2 even. When n is odd the sum is? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The sum of the first n terms of the series 1 ^ 2 + 2.2 ^ 2 + 3 ^ 2 + 2.4 ^ 2 + 5 ^ 2 + 2.6 ^ 2 +... is (n * (n + 1) ^ 2)/2 even. When n is odd the sum is?.
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