UPSC Exam > UPSC Questions > An object travel along a part ABC shown dista...
Start Learning for Free
An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples?
Most Upvoted Answer
An object travel along a part ABC shown distance is equal to AB + BC i...
Explanation of the scenario:
Distance traveled along a straight path (ABC) is 7m and the displacement is 5m when an object moves along a semicircular path.
Distance vs Displacement:
- Distance is the total length of the path covered by the object, while displacement is the shortest distance between the initial and final positions of the object.
- In this case, the distance traveled along the straight path ABC is 7m, while the displacement along the semicircular path is 5m.
Distance along the straight path ABC:
- Distance traveled along AB = 4m
- Distance traveled along BC = 3m
- Total distance traveled along ABC = 4m + 3m = 7m
Displacement along the semicircular path:
- Displacement = √(AB² + BC²) = √(4² + 3²) = √(16 + 9) = √25 = 5m
- The displacement is the distance between points A and C, which is equal to 5m.
Explanation of the semicircular path:
- When an object moves along a semicircular path, the distance traveled along the path (ACB) is equal to the circumference of the semicircle, which is half the circumference of a full circle (πR).
- The displacement (AOB) is equal to twice the radius of the semicircle (2R).
Example:
- Consider a semicircular track with a radius of 2m. If an object moves from point B along the semicircular path to point A, the distance traveled along the path (ACB) would be half the circumference of the circle, which is π*2 = 2πm.
- The displacement (AOB) would be twice the radius of the semicircle, which is 2*2 = 4m.
Distance traveled along a straight path (ABC) is 7m and the displacement is 5m when an object moves along a semicircular path.
Distance vs Displacement:
- Distance is the total length of the path covered by the object, while displacement is the shortest distance between the initial and final positions of the object.
- In this case, the distance traveled along the straight path ABC is 7m, while the displacement along the semicircular path is 5m.
Distance along the straight path ABC:
- Distance traveled along AB = 4m
- Distance traveled along BC = 3m
- Total distance traveled along ABC = 4m + 3m = 7m
Displacement along the semicircular path:
- Displacement = √(AB² + BC²) = √(4² + 3²) = √(16 + 9) = √25 = 5m
- The displacement is the distance between points A and C, which is equal to 5m.
Explanation of the semicircular path:
- When an object moves along a semicircular path, the distance traveled along the path (ACB) is equal to the circumference of the semicircle, which is half the circumference of a full circle (πR).
- The displacement (AOB) is equal to twice the radius of the semicircle (2R).
Example:
- Consider a semicircular track with a radius of 2m. If an object moves from point B along the semicircular path to point A, the distance traveled along the path (ACB) would be half the circumference of the circle, which is π*2 = 2πm.
- The displacement (AOB) would be twice the radius of the semicircle, which is 2*2 = 4m.
Attention UPSC Students!
To make sure you are not studying endlessly, EduRev has designed UPSC study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UPSC.
|
Explore Courses for UPSC exam
|
|
Similar UPSC Doubts
Top Courses for UPSCView all
An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples?
Question Description
An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples?.
An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples?.
Solutions for An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples? in English & in Hindi are available as part of our courses for UPSC.
Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples? defined & explained in the simplest way possible. Besides giving the explanation of
An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples?, a detailed solution for An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples? has been provided alongside types of An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples? theory, EduRev gives you an
ample number of questions to practice An object travel along a part ABC shown distance is equal to AB + BC is equal to 4 + 3 is equal to 7 m displacement is equal to AC is equal to root of a b square + BC square is equal to route of square + 3 square is equal to 5 M when a body moves from pointed B along a semicircular path shown in figure distance ACB = pie R displacement aob is equal to 2r explain with examples? tests, examples and also practice UPSC tests.
|
|
Explore Courses for UPSC exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup