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Two student appeared at an examination one of them secured 10 marks more than the other and his marks was 60% of the sum of their marks the marks obtained by the better student are?
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Two student appeared at an examination one of them secured 10 marks mo...
Given Information:
- Let the marks obtained by the better student be x.
- The other student obtained 10 marks less than the better student, so their marks would be (x - 10).
- The better student's marks are 60% of the sum of their marks, which can be represented as:
x = 0.6(x + (x - 10))

Solving the Equation:
- Simplifying the equation:
x = 0.6(2x - 10)
x = 1.2x - 6
6 = 0.2x
x = 30

Calculating the Marks:
- The better student's marks are x = 30.
- The other student's marks would be (30 - 10) = 20.

Conclusion:
- The better student obtained 30 marks, while the other student obtained 20 marks in the examination.
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Two student appeared at an examination one of them secured 10 marks more than the other and his marks was 60% of the sum of their marks the marks obtained by the better student are?
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