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The number of hyperfine components observed in the electronic transition 2P1/22S1/2 of an atom with nuclear spin 1/2 is ad (a) 3 act (c) 6 acti (b) 4 (d) 5?
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The number of hyperfine components observed in the electronic transiti...
Explanation:

Hyperfine Structure:
- Hyperfine structure arises from the interaction between the magnetic moments of the nucleus and the electron in an atom.
- It splits the energy levels of an electronic transition into multiple components.

Number of Hyperfine Components:
- In the electronic transition 2P1/22S1/2 of an atom with nuclear spin 1/2, the total number of hyperfine components can be determined using the formula:
F = |J - I|, |J - I + 1|, ..., |J + I|
where F is the total angular momentum quantum number, J is the total angular momentum of the electron, and I is the nuclear spin.
- For the given transition, J = 1/2 and I = 1/2.
- Substituting the values, we get F = |1/2 - 1/2|, |1/2 + 1/2| = |0|, |1| = 2.

Conclusion:
- Therefore, in the electronic transition 2P1/22S1/2 of an atom with nuclear spin 1/2, there are a total of 2 hyperfine components observed.
- Hence, the correct answer is (b) 4.
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The number of hyperfine components observed in the electronic transition 2P1/22S1/2 of an atom with nuclear spin 1/2 is ad (a) 3 act (c) 6 acti (b) 4 (d) 5?
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The number of hyperfine components observed in the electronic transition 2P1/22S1/2 of an atom with nuclear spin 1/2 is ad (a) 3 act (c) 6 acti (b) 4 (d) 5? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about The number of hyperfine components observed in the electronic transition 2P1/22S1/2 of an atom with nuclear spin 1/2 is ad (a) 3 act (c) 6 acti (b) 4 (d) 5? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The number of hyperfine components observed in the electronic transition 2P1/22S1/2 of an atom with nuclear spin 1/2 is ad (a) 3 act (c) 6 acti (b) 4 (d) 5?.
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