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In a two dogit number the sum of the two digit is 8 if18 is added to the number its digit reversed. find the number?
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In a two dogit number the sum of the two digit is 8 if18 is added to t...
Given Information:
In a two-digit number, the sum of the two digits is 8. When 18 is added to the number, its digits are reversed.

Let's Break Down the Problem:

Step 1: Identify the Two-Digit Number
Let the two-digit number be represented by 10x + y, where x is the digit in the tens place and y is the digit in the units place.
According to the given information, the sum of the digits is 8:
x + y = 8

Step 2: Formulate the Equation
When 18 is added to the number, its digits are reversed:
10x + y + 18 = 10y + x

Step 3: Solve the Equations
From the first equation, x + y = 8, we can solve for x in terms of y:
x = 8 - y
Substitute x = 8 - y into the second equation:
10(8 - y) + y + 18 = 10y + 8 - y
80 - 10y + y + 18 = 10y + 8 - y
80 - 9y + 18 = 9y + 8
98 - 9y = 9y + 8
98 - 8 = 9y + 9y
90 = 18y
y = 5
Now that we have found y, we can find x using x = 8 - y:
x = 8 - 5
x = 3

Step 4: Determine the Two-Digit Number
Therefore, the two-digit number is 10x + y = 10(3) + 5 = 30 + 5 = 35.

Conclusion:
The two-digit number is 35.
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In a two dogit number the sum of the two digit is 8 if18 is added to the number its digit reversed. find the number?
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