The K alpha and K Beta rays of molybdenum have wave- lengths 0.71Å and...
Calculating the wavelength of Lalpha X-rays
- The relationship between the wavelengths of different X-rays is given by Moseley's law, which states that the square root of the frequency of the Kalpha line is proportional to the atomic number Z.
- Mathematically, this can be expressed as √(1/λ) = k(Z - σ)
- Here, λ is the wavelength of the X-ray, Z is the atomic number of the element, k is a constant, and σ is the screening constant.
- By using the given wavelengths of Kalpha and Kbeta lines for molybdenum, we can find the value of k.
- Once k is determined, we can use this information to calculate the wavelength of the Lalpha X-rays for molybdenum.
Calculations
- Given: λ(Kalpha) = 0.71Å and λ(Kbeta) = 0.63Å
- Using the above wavelengths and the corresponding atomic numbers for molybdenum, we can determine the value of k.
- By substituting the values into the Moseley's law equation, we can calculate the wavelength of Lalpha X-rays for molybdenum.
Final Answer
- After performing the calculations, the wavelength of Lalpha X-rays for molybdenum is found to be approximately 4.64Å.
- Therefore, the correct answer is (a) 4.64Å.