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Q11 An organic compound exhibits the following 'H NMR spectra data
[NET June 2013]
87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )?
[NET June 2013]
87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )?
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Q11 An organic compound exhibits the following 'H NMR spectra data[NET...
Interpreting the H NMR spectra data
- Chemical shifts: The chemical shifts in the NMR spectra data indicate the resonance frequencies of the hydrogens in the compound.
- Multiplicity: The multiplicity of the peaks (singlet, doublet, triplet, etc.) provides information about the neighboring hydrogens.
- Integration: The integration values represent the relative number of hydrogens contributing to each peak.
- Coupling constants: The coupling constants (J values) provide information about the splitting patterns in the NMR spectra.
- Peak analysis: From the given data, we can deduce that the compound contains different types of hydrogen environments.
- Peak at 2.4 ppm: This peak corresponds to a methyl group (3H, s), indicating a singlet due to the absence of neighboring hydrogens.
- Peak at 4.10 ppm: This peak represents a methylene group (2H, t, J = 7.2 Hz), showing a triplet pattern with a coupling constant of 7.2 Hz.
- Peak at 6.80 ppm: This peak indicates a benzyl proton (2H, d, J = 8 Hz), displaying a doublet pattern with a coupling constant of 8 Hz.
- Peak at 7.80 ppm: This peak corresponds to another benzyl proton (2H, d, J = 8 Hz), also showing a doublet pattern with a coupling constant of 8 Hz.
- Peak at 1.25 ppm: This peak represents a methyl group (3H, t, J = 7.2 Hz), displaying a triplet pattern with a coupling constant of 7.2 Hz.
By analyzing the chemical shifts, multiplicities, integration values, and coupling constants in the H NMR spectra data, we can deduce the structural information of the organic compound.
- Chemical shifts: The chemical shifts in the NMR spectra data indicate the resonance frequencies of the hydrogens in the compound.
- Multiplicity: The multiplicity of the peaks (singlet, doublet, triplet, etc.) provides information about the neighboring hydrogens.
- Integration: The integration values represent the relative number of hydrogens contributing to each peak.
- Coupling constants: The coupling constants (J values) provide information about the splitting patterns in the NMR spectra.
- Peak analysis: From the given data, we can deduce that the compound contains different types of hydrogen environments.
- Peak at 2.4 ppm: This peak corresponds to a methyl group (3H, s), indicating a singlet due to the absence of neighboring hydrogens.
- Peak at 4.10 ppm: This peak represents a methylene group (2H, t, J = 7.2 Hz), showing a triplet pattern with a coupling constant of 7.2 Hz.
- Peak at 6.80 ppm: This peak indicates a benzyl proton (2H, d, J = 8 Hz), displaying a doublet pattern with a coupling constant of 8 Hz.
- Peak at 7.80 ppm: This peak corresponds to another benzyl proton (2H, d, J = 8 Hz), also showing a doublet pattern with a coupling constant of 8 Hz.
- Peak at 1.25 ppm: This peak represents a methyl group (3H, t, J = 7.2 Hz), displaying a triplet pattern with a coupling constant of 7.2 Hz.
By analyzing the chemical shifts, multiplicities, integration values, and coupling constants in the H NMR spectra data, we can deduce the structural information of the organic compound.
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Q11 An organic compound exhibits the following 'H NMR spectra data[NET June 2013]87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )?
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Q11 An organic compound exhibits the following 'H NMR spectra data[NET June 2013]87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Q11 An organic compound exhibits the following 'H NMR spectra data[NET June 2013]87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q11 An organic compound exhibits the following 'H NMR spectra data[NET June 2013]87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )?.
Q11 An organic compound exhibits the following 'H NMR spectra data[NET June 2013]87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )? for UPSC 2025 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Q11 An organic compound exhibits the following 'H NMR spectra data[NET June 2013]87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )? covers all topics & solutions for UPSC 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q11 An organic compound exhibits the following 'H NMR spectra data[NET June 2013]87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )?.
Solutions for Q11 An organic compound exhibits the following 'H NMR spectra data[NET June 2013]87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )? in English & in Hindi are available as part of our courses for UPSC.
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Q11 An organic compound exhibits the following 'H NMR spectra data[NET June 2013]87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )?, a detailed solution for Q11 An organic compound exhibits the following 'H NMR spectra data[NET June 2013]87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )? has been provided alongside types of Q11 An organic compound exhibits the following 'H NMR spectra data[NET June 2013]87.80 (2H, d, J = 8Hz ) 6.80 (2H, d, J = 8Hz ), 4.10 (2H, 1, 1 = 7.2 Hz), 2.4 (3H, s), 1.25 (3H, t, J = 7.2Hz )? theory, EduRev gives you an
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