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In the 'H NMR spectrum recorded at 293 K, an organic compound (C₂H,NO), exhibited signals at 87.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is?
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In the 'H NMR spectrum recorded at 293 K, an organic compound (C₂H,NO)...
Identification of Organic Compound from H NMR Spectrum
Identifying an organic compound from its H NMR spectrum involves analyzing the signals and their integration values. In this case, the compound has signals at 87.8 (1H, s), 2.8 (3H, s), and 2.6 (3H, s) at a temperature of 293 K.

Signal Analysis
- The signal at 87.8 ppm corresponds to a singlet with 1 hydrogen, indicating a unique environment for that hydrogen atom.
- The signals at 2.8 ppm and 2.6 ppm are both singlets with 3 hydrogens each, suggesting methyl groups.

Compound Identification
Based on the signals observed in the H NMR spectrum, the compound can be identified as acetamide (C2H5NO).
- The signal at 87.8 ppm corresponds to the hydrogen attached to the nitrogen atom in acetamide.
- The signals at 2.8 ppm and 2.6 ppm correspond to the methyl groups in the acetamide molecule.

Conclusion
Therefore, the organic compound with the molecular formula C2H5NO, exhibiting signals at 87.8 (1H, s), 2.8 (3H, s), and 2.6 (3H, s) in the H NMR spectrum recorded at 293 K, is acetamide. This conclusion is drawn based on the chemical shifts and integration values of the signals observed in the spectrum.
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In the 'H NMR spectrum recorded at 293 K, an organic compound (C₂H,NO), exhibited signals at 87.8 (1H, s), 2.8 (3H, s), 2.6 (3H, s), the compound is?
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