Saturated Solution of Sodium Chloride at 29 Kelvin
To calculate the concentration of a saturated solution of sodium chloride (NaCl) at 29 Kelvin, we start with the given data:
- **Mass of Sodium Chloride (NaCl)**: 36 grams
- **Mass of Water**: 100 grams

Understanding Solubility
- Sodium chloride is highly soluble in water, but its solubility varies with temperature. At low temperatures, the solubility decreases.

Calculation of Concentration
1. **Determine the Mass of Solvent**:
- Since we have 100 grams of water, this is our solvent.
2. **Calculate Molar Mass of NaCl**:
- Molar mass of NaCl = 22.99 g/mol (Na) + 35.45 g/mol (Cl) = **58.44 g/mol**.
3. **Calculate Moles of NaCl**:
- Moles of NaCl = Mass / Molar Mass = 36 g / 58.44 g/mol ≈ **0.616 moles**.
4. **Calculate Concentration**:
- Concentration (C) is defined as the number of moles of solute per liter of solution.
- To find the volume of water, we assume the density is approximately 1 g/mL.
- Volume of water = Mass of water / Density = 100 g / 1 g/mL = **100 mL** = **0.1 L**.
5. **Final Concentration Calculation**:
- Concentration (C) = Moles of NaCl / Volume of solution = 0.616 moles / 0.1 L = **6.16 M**.

Conclusion
- The concentration of the saturated solution of sodium chloride at 29 Kelvin is approximately **6.16 M**. This indicates a very concentrated solution, which may lead to precipitation if the temperature rises, as solubility increases with temperature.